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@ -8,6 +8,7 @@ from abc import ABCMeta, abstractmethod
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import warnings
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import warnings
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import numpy as np
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import numpy as np
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from numpy import pi, sqrt, exp, percentile
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from numpy import pi, sqrt, exp, percentile
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from numpy.fft import fft, ifft
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from scipy import optimize, linalg
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from scipy import optimize, linalg
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from scipy.special import gamma
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from scipy.special import gamma
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from wafo.misc import tranproc # , trangood
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from wafo.misc import tranproc # , trangood
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@ -564,6 +565,12 @@ class Kernel(object):
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def effective_support(self):
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def effective_support(self):
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return self.kernel.effective_support()
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return self.kernel.effective_support()
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def get_amise_constant(self, n):
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# R= int(mkernel(x)^2), mu2= int(x^2*mkernel(x))
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mu2, R = self.stats()[:2]
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amise_constant = (8 * sqrt(pi) * R / (3 * mu2 ** 2 * n)) ** (1. / 5)
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return amise_constant
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def hns(self, data):
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def hns(self, data):
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"""Returns Normal Scale Estimate of Smoothing Parameter.
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"""Returns Normal Scale Estimate of Smoothing Parameter.
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@ -615,9 +622,7 @@ class Kernel(object):
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a = np.atleast_2d(data)
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a = np.atleast_2d(data)
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n = a.shape[1]
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n = a.shape[1]
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# R= int(mkernel(x)^2), mu2= int(x^2*mkernel(x))
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amise_constant = self.get_amise_constant(n)
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mu2, R, _Rdd = self.stats()
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amise_constant = (8 * sqrt(pi) * R / (3 * mu2 ** 2 * n)) ** (1. / 5)
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iqr = iqrange(a, axis=1) # interquartile range
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iqr = iqrange(a, axis=1) # interquartile range
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std_a = np.std(a, axis=1, ddof=1)
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std_a = np.std(a, axis=1, ddof=1)
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# use of interquartile range guards against outliers.
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# use of interquartile range guards against outliers.
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@ -737,6 +742,10 @@ class Kernel(object):
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cov_a = np.cov(a)
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cov_a = np.cov(a)
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return scale * linalg.sqrtm(cov_a).real * n ** (-1. / (d + 4))
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return scale * linalg.sqrtm(cov_a).real * n ** (-1. / (d + 4))
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def get_ste_constant(self, n):
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mu2, R = self.stats()[:2]
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return R / (mu2 ** (2) * n)
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def hste(self, data, h0=None, inc=128, maxit=100, releps=0.01, abseps=0.0):
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def hste(self, data, h0=None, inc=128, maxit=100, releps=0.01, abseps=0.0):
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'''HSTE 2-Stage Solve the Equation estimate of smoothing parameter.
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'''HSTE 2-Stage Solve the Equation estimate of smoothing parameter.
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@ -765,17 +774,12 @@ class Kernel(object):
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'Kernel smoothing'
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'Kernel smoothing'
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Chapman and Hall, pp 74--75
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Chapman and Hall, pp 74--75
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'''
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'''
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# TODO: NB: this routine can be made faster:
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# TODO: replace the iteration in the end with a Newton Raphson scheme
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A = np.atleast_2d(data)
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A = np.atleast_2d(data)
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d, n = A.shape
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d, n = A.shape
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# R = int(mkernel(x)^2), mu2 = int(x^2*mkernel(x))
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amise_constant = self.get_amise_constant(n)
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mu2, R, _Rdd = self.stats()
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ste_constant = self.get_ste_constant(n)
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amise_constant = (8 * sqrt(pi) * R / (3 * mu2 ** 2 * n)) ** (1. / 5)
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ste_constant = R / (mu2 ** (2) * n)
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sigmaA = self.hns(A) / amise_constant
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sigmaA = self.hns(A) / amise_constant
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if h0 is None:
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if h0 is None:
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@ -784,21 +788,12 @@ class Kernel(object):
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h = np.asarray(h0, dtype=float)
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h = np.asarray(h0, dtype=float)
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nfft = inc * 2
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nfft = inc * 2
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amin = A.min(axis=1) # Find the minimum value of A.
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amax = A.max(axis=1) # Find the maximum value of A.
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arange = amax - amin # Find the range of A.
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# xa holds the x 'axis' vector, defining a grid of x values where
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ax1, bx1 = self._get_grid_limits(A)
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# the k.d. function will be evaluated.
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ax1 = amin - arange / 8.0
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bx1 = amax + arange / 8.0
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kernel2 = Kernel('gauss')
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kernel2 = Kernel('gauss')
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mu2, R, _Rdd = kernel2.stats()
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mu2, R, _Rdd = kernel2.stats()
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ste_constant2 = R / (mu2 ** (2) * n)
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ste_constant2 = kernel2.get_ste_constant(n)
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fft = np.fft.fft
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ifft = np.fft.ifft
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for dim in range(d):
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for dim in range(d):
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s = sigmaA[dim]
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s = sigmaA[dim]
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@ -822,8 +817,7 @@ class Kernel(object):
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# Estimate psi6 given g2.
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# Estimate psi6 given g2.
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# kernel weights.
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# kernel weights.
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kw4, kw6 = kernel2.deriv4_6_8_10(xn / g2, numout=2)
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kw4, kw6 = kernel2.deriv4_6_8_10(xn / g2, numout=2)
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# Apply fftshift to kw.
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kw = np.r_[kw6, 0, kw6[-1:0:-1]] # Apply fftshift to kw.
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kw = np.r_[kw6, 0, kw6[-1:0:-1]]
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z = np.real(ifft(fft(c, nfft) * fft(kw))) # convolution.
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z = np.real(ifft(fft(c, nfft) * fft(kw))) # convolution.
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psi6 = np.sum(c * z[:inc]) / (n * (n - 1) * g2 ** 7)
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psi6 = np.sum(c * z[:inc]) / (n * (n - 1) * g2 ** 7)
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@ -892,24 +886,11 @@ class Kernel(object):
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'''
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'''
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A = np.atleast_2d(data)
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A = np.atleast_2d(data)
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d, n = A.shape
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d, n = A.shape
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ste_constant = self.get_ste_constant(n)
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# R = int(mkernel(x)^2), mu2 = int(x^2*mkernel(x))
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ax1, bx1 = self._get_grid_limits(A)
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mu2, R, _Rdd = self.stats()
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ste_constant = R / (n * mu2 ** 2)
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amin = A.min(axis=1) # Find the minimum value of A.
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amax = A.max(axis=1) # Find the maximum value of A.
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arange = amax - amin # Find the range of A.
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# xa holds the x 'axis' vector, defining a grid of x values where
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# the k.d. function will be evaluated.
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ax1 = amin - arange / 8.0
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bx1 = amax + arange / 8.0
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kernel2 = Kernel('gauss')
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kernel2 = Kernel('gauss')
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mu2, R, _Rdd = kernel2.stats()
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ste_constant2 = kernel2.get_ste_constant(n)
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ste_constant2 = R / (mu2 ** (2) * n)
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def fixed_point(t, N, I, a2):
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def fixed_point(t, N, I, a2):
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''' this implements the function t-zeta*gamma^[L](t)'''
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''' this implements the function t-zeta*gamma^[L](t)'''
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@ -929,8 +910,7 @@ class Kernel(object):
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h = np.empty(d)
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h = np.empty(d)
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for dim in range(d):
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for dim in range(d):
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ax = ax1[dim]
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ax, bx = ax1[dim], bx1[dim]
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bx = bx1[dim]
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xa = np.linspace(ax, bx, inc)
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xa = np.linspace(ax, bx, inc)
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R = bx - ax
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R = bx - ax
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@ -942,13 +922,11 @@ class Kernel(object):
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I = np.asfarray(np.arange(1, inc)) ** 2
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I = np.asfarray(np.arange(1, inc)) ** 2
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a2 = (a[1:] / 2) ** 2
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a2 = (a[1:] / 2) ** 2
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def fun(t):
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return fixed_point(t, N, I, a2)
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x = np.linspace(0, 0.1, 150)
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x = np.linspace(0, 0.1, 150)
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ai = x[0]
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ai = x[0]
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f0 = fun(ai)
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f0 = fixed_point(ai, N, I, a2)
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for bi in x[1:]:
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for bi in x[1:]:
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f1 = fun(bi)
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f1 = fixed_point(bi, N, I, a2)
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if f1 * f0 <= 0:
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if f1 * f0 <= 0:
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# print('ai = %g, bi = %g' % (ai,bi))
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# print('ai = %g, bi = %g' % (ai,bi))
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break
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break
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@ -961,10 +939,12 @@ class Kernel(object):
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# use fzero to solve the equation t=zeta*gamma^[5](t)
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# use fzero to solve the equation t=zeta*gamma^[5](t)
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try:
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try:
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t_star = optimize.brentq(fun, a=ai, b=bi)
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t_star = optimize.brentq(lambda t: fixed_point(t, N, I, a2),
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except:
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a=ai, b=bi)
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except Exception as err:
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t_star = 0.28 * N ** (-2. / 5)
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t_star = 0.28 * N ** (-2. / 5)
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warnings.warn('Failure in obtaining smoothing parameter')
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warnings.warn('Failure in obtaining smoothing parameter'
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' ({})'.format(str(err)))
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# smooth the discrete cosine transform of initial data using t_star
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# smooth the discrete cosine transform of initial data using t_star
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# a_t = a*exp(-np.arange(inc)**2*pi**2*t_star/2)
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# a_t = a*exp(-np.arange(inc)**2*pi**2*t_star/2)
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@ -1022,11 +1002,8 @@ class Kernel(object):
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A = np.atleast_2d(data)
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A = np.atleast_2d(data)
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d, n = A.shape
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d, n = A.shape
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# R= int(mkernel(x)^2), mu2= int(x^2*mkernel(x))
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amise_constant = self.get_amise_constant(n)
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mu2, R, _Rdd = self.stats()
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ste_constant = self.get_ste_constant(n)
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amise_constant = (8 * sqrt(pi) * R / (3 * mu2 ** 2 * n)) ** (1. / 5)
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ste_constant = R / (mu2 ** (2) * n)
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sigmaA = self.hns(A) / amise_constant
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sigmaA = self.hns(A) / amise_constant
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if h0 is None:
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if h0 is None:
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@ -1035,18 +1012,9 @@ class Kernel(object):
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h = np.asarray(h0, dtype=float)
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h = np.asarray(h0, dtype=float)
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nfft = inc * 2
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nfft = inc * 2
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amin = A.min(axis=1) # Find the minimum value of A.
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amax = A.max(axis=1) # Find the maximum value of A.
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arange = amax - amin # Find the range of A.
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# xa holds the x 'axis' vector, defining a grid of x values where
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# the k.d. function will be evaluated.
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ax1 = amin - arange / 8.0
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ax1, bx1 = self._get_grid_limits(A)
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bx1 = amax + arange / 8.0
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fft = np.fft.fft
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ifft = np.fft.ifft
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for dim in range(d):
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for dim in range(d):
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s = sigmaA[dim]
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s = sigmaA[dim]
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datan = A[dim] / s
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datan = A[dim] / s
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@ -1078,8 +1046,7 @@ class Kernel(object):
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psi4 = delta * z.sum()
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psi4 = delta * z.sum()
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h1 = (ste_constant / psi4) ** (1. / 5)
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h1 = (ste_constant / psi4) ** (1. / 5)
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if count >= maxit:
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_assert_warn(count < maxit, 'The obtained value did not converge.')
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warnings.warn('The obtained value did not converge.')
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h[dim] = h1 * s
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h[dim] = h1 * s
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# end # for dim loop
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# end # for dim loop
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@ -1132,11 +1099,8 @@ class Kernel(object):
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A = np.atleast_2d(data)
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A = np.atleast_2d(data)
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d, n = A.shape
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d, n = A.shape
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# R= int(mkernel(x)^2), mu2= int(x^2*mkernel(x))
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amise_constant = self.get_amise_constant(n)
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mu2, R, _Rdd = self.stats()
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ste_constant = self.get_ste_constant(n)
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amise_constant = (8 * sqrt(pi) * R / (3 * mu2 ** 2 * n)) ** (1. / 5)
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ste_constant = R / (mu2 ** (2) * n)
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sigmaA = self.hns(A) / amise_constant
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sigmaA = self.hns(A) / amise_constant
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if hvec is None:
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if hvec is None:
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@ -1148,21 +1112,12 @@ class Kernel(object):
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score = np.zeros(steps)
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score = np.zeros(steps)
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nfft = inc * 2
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nfft = inc * 2
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amin = A.min(axis=1) # Find the minimum value of A.
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amax = A.max(axis=1) # Find the maximum value of A.
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arange = amax - amin # Find the range of A.
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# xa holds the x 'axis' vector, defining a grid of x values where
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ax1, bx1 = self._get_grid_limits(A)
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# the k.d. function will be evaluated.
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ax1 = amin - arange / 8.0
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bx1 = amax + arange / 8.0
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kernel2 = Kernel('gauss')
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kernel2 = Kernel('gauss')
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mu2, R, _Rdd = kernel2.stats()
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mu2 = kernel2.stats()[0]
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ste_constant2 = R / (mu2 ** (2) * n)
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ste_constant2 = kernel2.get_ste_constant(n)
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fft = np.fft.fft
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ifft = np.fft.ifft
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h = np.zeros(d)
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h = np.zeros(d)
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hvec = hvec * (ste_constant2 / ste_constant) ** (1. / 5.)
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hvec = hvec * (ste_constant2 / ste_constant) ** (1. / 5.)
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@ -1220,8 +1175,9 @@ class Kernel(object):
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sig1 = sqrt(2 * hvec[i] ** 2 + 2 * g ** 2)
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sig1 = sqrt(2 * hvec[i] ** 2 + 2 * g ** 2)
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sig2 = sqrt(hvec[i] ** 2 + 2 * g ** 2)
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sig2 = sqrt(hvec[i] ** 2 + 2 * g ** 2)
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sig3 = sqrt(2 * g ** 2)
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sig3 = sqrt(2 * g ** 2)
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term2 = np.sum(kernel2(Y / sig1) / sig1 - 2 * kernel2(
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term2 = np.sum(kernel2(Y / sig1) / sig1 -
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Y / sig2) / sig2 + kernel2(Y / sig3) / sig3)
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2 * kernel2(Y / sig2) / sig2 +
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kernel2(Y / sig3) / sig3)
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score[i] = 1. / (n * hvec[i] * 2. * sqrt(pi)) + term2 / n ** 2
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score[i] = 1. / (n * hvec[i] * 2. * sqrt(pi)) + term2 / n ** 2
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@ -1240,6 +1196,11 @@ class Kernel(object):
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return h * sigmaA, score, hvec
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return h * sigmaA, score, hvec
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return h * sigmaA
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return h * sigmaA
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def _get_grid_limits(self, data):
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min_a, max_a = data.min(axis=1), data.max(axis=1)
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offset = (max_a - min_a) / 8.0
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return min_a - offset, max_a + offset
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def hldpi(self, data, L=2, inc=128):
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def hldpi(self, data, L=2, inc=128):
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'''HLDPI L-stage Direct Plug-In estimate of smoothing parameter.
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'''HLDPI L-stage Direct Plug-In estimate of smoothing parameter.
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@ -1273,31 +1234,17 @@ class Kernel(object):
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A = np.atleast_2d(data)
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A = np.atleast_2d(data)
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d, n = A.shape
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d, n = A.shape
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# R= int(mkernel(x)^2), mu2= int(x^2*mkernel(x))
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amise_constant = self.get_amise_constant(n)
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mu2, R, _Rdd = self.stats()
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ste_constant = self.get_ste_constant(n)
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amise_constant = (8 * sqrt(pi) * R / (3 * n * mu2 ** 2)) ** (1. / 5)
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ste_constant = R / (n * mu2 ** 2)
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sigmaA = self.hns(A) / amise_constant
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sigmaA = self.hns(A) / amise_constant
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nfft = inc * 2
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nfft = inc * 2
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amin = A.min(axis=1) # Find the minimum value of A.
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ax1, bx1 = self._get_grid_limits(A)
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amax = A.max(axis=1) # Find the maximum value of A.
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arange = amax - amin # Find the range of A.
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# xa holds the x 'axis' vector, defining a grid of x values where
|
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# the k.d. function will be evaluated.
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ax1 = amin - arange / 8.0
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bx1 = amax + arange / 8.0
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kernel2 = Kernel('gauss')
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kernel2 = Kernel('gauss')
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mu2, _R, _Rdd = kernel2.stats()
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mu2, _R, _Rdd = kernel2.stats()
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fft = np.fft.fft
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ifft = np.fft.ifft
|
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h = np.zeros(d)
|
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h = np.zeros(d)
|
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|
for dim in range(d):
|
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for dim in range(d):
|
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s = sigmaA[dim]
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s = sigmaA[dim]
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@ -1330,8 +1277,8 @@ class Kernel(object):
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kw0 = kernel2.deriv4_6_8_10(xn / gi, numout=ix)
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|
kw0 = kernel2.deriv4_6_8_10(xn / gi, numout=ix)
|
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|
if ix > 1:
|
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|
if ix > 1:
|
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|
kw0 = kw0[-1]
|
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|
kw0 = kw0[-1]
|
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|
|
# Apply 'fftshift' to kw.
|
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|
|
kw = np.r_[kw0, 0, kw0[inc - 1:0:-1]]
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kw = np.r_[kw0, 0, kw0[inc - 1:0:-1]] # Apply 'fftshift'
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|
# Perform the convolution.
|
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|
|
# Perform the convolution.
|
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|
|
z = np.real(ifft(fft(c, nfft) * fft(kw)))
|
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|
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z = np.real(ifft(fft(c, nfft) * fft(kw)))
|
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