Add nielsen_volumes.py
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def491cea5
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8ca180f93f
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#
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import scipy.interpolate
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import numpy as np
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import copy
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import math
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repose_angle=34 #angle of repose of sand
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repose_slope=1/math.tan(math.radians(repose_angle))
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def insertZerochainage(chainage, elevation):
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#this inserts a 0 every time the profile crosses the axis
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#need to update the chainage elevation for every point that drops below the required chainage
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ii=0
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while ii<len(elevation):
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if ii==0 and elevation[ii]<0:
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while elevation[ii]<0:
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ii=ii+1
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try:
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beachslope = 1/((elevation[ii-1] - elevation[ii])/(chainage[ii] - chainage[ii-1]))
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except:
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beachslope= 999
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chainageX= (elevation[ii-1]-0)*beachslope+chainage[ii-1]
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elevation.insert(ii,0)
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chainage.insert(ii,chainageX)
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ii=ii+1
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if elevation[ii]<0:
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try:
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beachslope = 1/((elevation[ii-1] - elevation[ii])/(chainage[ii] - chainage[ii-1]))
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except ZeroDivisionError:
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beachslope= 999
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chainageX= (elevation[ii-1]-0)*beachslope+chainage[ii-1]
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elevation.insert(ii,0)
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chainage.insert(ii,chainageX)
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ii=ii+1
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try:
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#finding where it crosses back over zero. If you reach the end of the list, return the list
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while elevation[ii]<0:
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ii=ii+1
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try:
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beachslope = 1/((elevation[ii-1] - elevation[ii])/(chainage[ii] - chainage[ii-1]))
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except ZeroDivisionError:
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beachslope= 999
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chainageX= (elevation[ii-1]-0)*beachslope+chainage[ii-1]
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elevation.insert(ii,0)
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chainage.insert(ii,chainageX)
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ii=ii+1
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except IndexError:
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return chainage, elevation
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else:
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ii=ii+1
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return chainage, elevation
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def custom_trap_rule(elevation,chainage):
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#so that it doesn't count any volume below zero as a negative
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#add a zero point every time the profile crosses the axis (note that the seaward zero has already been inserted)
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x,y=insertZerochainage(copy.copy(chainage), copy.copy(elevation))
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# add the final 0
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x,y = findZerochainage(x,y)
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i=1
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area=0
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while i<len(y):
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if y[i]>=0 and y[i-1]>=0:
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area=area+0.5*(x[i]-x[i-1])*(y[i]+y[i-1])
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i=i+1
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return area
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def findIntersection(x11,y11,x12,y12,x21,y21,x22,y22):
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#find the intersection of a two lines defined by four points
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try:
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m1=(y12-y11)/(x12-x11)
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b1=y11-m1*x11
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except (ZeroDivisionError,FloatingPointError):
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x_inter=x11
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m2=(y22-y21)/(x22-x21)
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b2=y21-m2*x21
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y_inter=m2*x_inter+b2
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return x_inter, y_inter
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try:
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m2=(y22-y21)/(x22-x21)
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b2=y21-m2*x21
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except (ZeroDivisionError, FloatingPointError):
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x_inter=x21
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y_inter=m1*x_inter +b1
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return x_inter, y_inter
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x_inter=(b2-b1)/(m1-m2)
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y_inter=m1*x_inter+b1
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return x_inter, y_inter
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def findZerochainage(chainage0, elevation0, max_beach_slope=5, min_beach_slope=50):
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#often the photogrammetry has a repeated point at the end. Check for this and remove extra if required
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while chainage0[-1]==chainage0[-2] and elevation0[-1]==elevation0[-2]:
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chainage0 = chainage0[:-1]
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elevation0 = elevation0[:-1]
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#check if the profile ever goes below zero
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ii=len(elevation0)-1
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below_0=False
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while ii>len(elevation0)/2:
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if elevation0[ii]<0:
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below_0=True
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while elevation0[ii]<0:
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ii=ii-1
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j=ii+1 #so you don't have to search for this again
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ii=0
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else:
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ii=ii-1
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# if Below_0 = True, we can use the actual zero value
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if below_0==True:
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chainage0=chainage0[0:j+1]
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elevation0=elevation0[0:j+1]
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elevation_inter=scipy.interpolate.interp1d(elevation0[-2:],chainage0[-2:])
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chainage_0=float(elevation_inter(0))
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chainage0[j]=chainage_0
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elevation0[j]=0
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#otherwise need to extrapolate
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else:
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#find the slope between the last two points
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try:
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beachslope = 1/((elevation0[-2] - elevation0[-1])/(chainage0[-1] - chainage0[-2]))
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except ZeroDivisionError:
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beachslope= 999
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if beachslope>min_beach_slope:
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beachslope = min_beach_slope
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elif beachslope<max_beach_slope:
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beachslope = max_beach_slope
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chainageX=(elevation0[-1])*beachslope+chainage0[-1]
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if chainageX!=chainage0[-1]:
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chainage0.append(chainageX)
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elevation0.append(0)
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return chainage0,elevation0
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def insert_LL(chainage, elevation, LL):
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# insert an additional element to make LL an actual point
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elev_intr=scipy.interpolate.interp1d(chainage, elevation)
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elev_LL=float(elev_intr(LL))
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data=[[chainage[i], elevation[i]] for i in range(0, len(chainage))]
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data.append([LL,elev_LL])
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data.sort()
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chainage=[data[i][0] for i in range(0, len(data))]
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elevation=[data[i][1] for i in range(0, len(data))]
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return chainage, elevation, elev_LL
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def volume_available (chainage, elevation, LL):
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chainage, elevation, LL_z = insert_LL(chainage, elevation, LL)
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index_LL=0
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while chainage[index_LL]!=LL:
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index_LL=index_LL+1
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bottom_ZSA_x = LL + LL_z/repose_slope
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bottom_ZSA_y=0
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mid_ZWI_x= LL+(LL_z - 2)/(2*math.tan(math.radians(repose_angle)))
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mid_ZWI_y = 2
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bottom_ZWI_x=mid_ZWI_x+ mid_ZWI_y*10
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bottom_ZWI_y = 0
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x,y=findIntersection(LL,LL_z,bottom_ZSA_x,bottom_ZSA_y, mid_ZWI_x, mid_ZWI_y, bottom_ZWI_x, bottom_ZWI_y )
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V1=custom_trap_rule(elevation[index_LL:], chainage[index_LL:])
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V2=custom_trap_rule([ LL_z,mid_ZWI_y, bottom_ZWI_y],[LL,mid_ZWI_x,bottom_ZWI_x])
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volume=V1-V2
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return volume
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