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66 lines
2.0 KiB
Python
66 lines
2.0 KiB
Python
# -*- coding: utf-8 -*-
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"""
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f2py c_library.pyf c_functions.c -c
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See also http://www.scipy.org/Cookbook/CompilingExtensionsOnWindowsWithMinGW
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"""
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import os
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import sys
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def which(program):
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"""
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Return filepath to program if it exists
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In order to test if a certain executable exists, it will search for the
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program name in the environment variables.
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If program is a full path to an executable, it will check it exists
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Copied from:
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http://stackoverflow.com/questions/377017/test-if-executable-exists-in-python/
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It is supposed to mimic the UNIX command "which"
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"""
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def is_exe(fpath):
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return os.path.exists(fpath) and os.access(fpath, os.X_OK)
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fpath, unused_fname = os.path.split(program)
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if fpath:
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if is_exe(program):
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return program
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else:
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for path in os.environ["PATH"].split(os.pathsep):
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exe_file = os.path.join(path, program)
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if is_exe(exe_file):
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return exe_file
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return None
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def f2py_call_str():
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'''Return which f2py callable is in the path regardless of platform'''
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# define possible options:
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# on Arch Linux, python and f2py are the calls corresponding to python 3
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# and python2/f2py2 for python 2
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# other Linux versions might still use python/f2py for python 2
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if os.path.basename(sys.executable).endswith('2'):
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options = ('f2py2', 'f2py2.6', 'f2py2.7',)
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else: # on Windows and other Linux using python/f2py
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options = ('f2py.exe', 'f2py.bat', 'f2py', 'f2py2.6', 'f2py2.7',
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'f2py.py',)
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for k in options:
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if which(k):
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# Found the f2py path, no need to look further
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f2py_call = k
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f2py_path = which(k)
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break
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try:
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print 'found f2py in:', f2py_path
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return f2py_call
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except NameError:
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raise UserWarning('Couldn\'t locate f2py. '
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'Should be part of NumPy installation.')
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