From dd9cfb63adf6a593f89acbdf8af1a72c7e49fd18 Mon Sep 17 00:00:00 2001 From: pbrod Date: Sun, 29 Nov 2015 15:27:21 +0100 Subject: [PATCH] Renamed TestFunctions to ExampleFunctions in order to not confuse pytest. --- wafo/padua.py | 91 ++++++++++++++++++++++++++++++--------------------- 1 file changed, 53 insertions(+), 38 deletions(-) diff --git a/wafo/padua.py b/wafo/padua.py index 4aa31a2..d43f7a4 100644 --- a/wafo/padua.py +++ b/wafo/padua.py @@ -85,8 +85,11 @@ Contents.m : Contents file for Matlab from __future__ import division import numpy as np from numpy.fft import fft +from wafo.dctpack import dct +# from scipy.fftpack.realtransforms import dct -class TestFunctions(object): + +class _ExampleFunctions(object): ''' Computes test function in the points (x, y) @@ -159,7 +162,8 @@ class TestFunctions(object): def exp_fun1(x, y): ''' The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 2000, - is 2.1234596326670683e+001 with an estimated absolute error of 7.11e-015. + is 2.1234596326670683e+001 with an estimated absolute error of + 7.11e-015. ''' return np.exp((x - 0.5)**2 + (y - 0.5)**2) @@ -167,7 +171,8 @@ class TestFunctions(object): def exp_fun100(x, y): '''The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 2000, - is 3.1415926535849605e-002 with an estimated absolute error of 3.47e-017. + is 3.1415926535849605e-002 with an estimated absolute error of + 3.47e-017. ''' return np.exp(-100 * ((x - 0.5)**2 + (y - 0.5)**2)) @@ -175,7 +180,8 @@ class TestFunctions(object): def cos30(x, y): ''' The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 500, - is 4.3386955120336568e-003 with an estimated absolute error of 2.95e-017. + is 4.3386955120336568e-003 with an estimated absolute error of + 2.95e-017. ''' return np.cos(30 * (x + y)) @@ -194,7 +200,8 @@ class TestFunctions(object): is up to machine precision is 5.524391382167263 (see ref. 6). 2. The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 500, - is 5.5243913821672628e+000 with an estimated absolute error of 0.00e+000. + is 5.5243913821672628e+000 with an estimated absolute error of + 0.00e+000. 2D modification of an example by L.N.Trefethen (see ref. 7), f(x)=exp(x). ''' @@ -209,7 +216,8 @@ class TestFunctions(object): up to machine precision, is 0.597388947274307 (see ref. 6). The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 500, - is 5.9738894727430725e-001 with an estimated absolute error of 0.00e+000. + is 5.9738894727430725e-001 with an estimated absolute error of + 0.00e+000. 2D modification of an example by L.N.Trefethen (see ref. 7), f(x)=1/(1+16*x^2). @@ -223,7 +231,8 @@ class TestFunctions(object): up to machine precision, is 2.508723139534059 (see ref. 6). The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 500, - is 2.5087231395340579e+000 with an estimated absolute error of 0.00e+000. + is 2.5087231395340579e+000 with an estimated absolute error of + 0.00e+000. 2D modification of an example by L.N.Trefethen (see ref. 7), f(x)=abs(x)^3. @@ -237,7 +246,8 @@ class TestFunctions(object): up to machine precision, is 2.230985141404135 (see ref. 6). The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 500, - is 2.2309851414041333e+000 with an estimated absolute error of 2.66e-015. + is 2.2309851414041333e+000 with an estimated absolute error of + 2.66e-015. 2D modification of an example by L.N.Trefethen (see ref. 7), f(x)=exp(-x^2). @@ -251,7 +261,8 @@ class TestFunctions(object): up to machine precision, is 0.853358758654305 (see ref. 6). The value of the definite integral on the square [-1,1] x [-1,1], obtained using a Padua Points cubature formula of degree 2000, - is 8.5335875865430544e-001 with an estimated absolute error of 3.11e-015. + is 8.5335875865430544e-001 with an estimated absolute error of + 3.11e-015. 2D modification of an example by L.N.Trefethen (see ref. 7), f(x)=exp(-1/x^2). @@ -269,7 +280,7 @@ class TestFunctions(object): s.exp_fun100, s.cos30, s.constant, s.exp_xy, s.runge, s.abs_cubed, s.gauss, s.exp_inv] return test_function[id](x, y) -testfunct = TestFunctions() +example_functions = _ExampleFunctions() def _find_m(n): @@ -348,7 +359,6 @@ def padua_fit(Pad, fun, *args): ''' - N = np.shape(Pad)[1] # recover the degree n from N = (n+1)(n+2)/2 n = int(round(-3 + np.sqrt(1 + 8 * N)) / 2) @@ -375,54 +385,52 @@ def padua_fit(Pad, fun, *args): return C0f, error_estimate(C0f) + def paduavals2coefs(f): - useFFTwhenNisMoreThan=100 + useFFTwhenNisMoreThan = 100 m = len(f) - n = int(round(-1.5 + np.sqrt(.25+2*m))) + n = int(round(-1.5 + np.sqrt(.25 + 2 * m))) x = padua_points(n) idx = _find_m(n) - w = 0*x[0] + 1./(n*(n+1)) + w = 0 * x[0] + 1. / (n * (n + 1)) idx1 = np.all(np.abs(x) == 1, axis=0) - w[idx1] = .5*w[idx1] + w[idx1] = .5 * w[idx1] idx2 = np.all(np.abs(x) != 1, axis=0) - w[idx2] = 2*w[idx2] + w[idx2] = 2 * w[idx2] - G = np.zeros(idx.max()+1) - G[idx] = 4*w*f + G = np.zeros(idx.max() + 1) + G[idx] = 4 * w * f - if ( n < useFFTwhenNisMoreThan ): - t1 = np.r_[0:n+1].reshape(-1, 1) - Tn1 = np.cos(t1*t1.T*np.pi/n) - t2 = np.r_[0:n+2].reshape(-1, 1) - Tn2 = np.cos(t2*t2.T*np.pi/(n+1)); - C = np.dot(Tn2, np.dot(G,Tn1)) + if (n < useFFTwhenNisMoreThan): + t1 = np.r_[0:n + 1].reshape(-1, 1) + Tn1 = np.cos(t1 * t1.T * np.pi / n) + t2 = np.r_[0:n + 2].reshape(-1, 1) + Tn2 = np.cos(t2 * t2.T * np.pi / (n + 1)) + C = np.dot(Tn2, np.dot(G, Tn1)) else: # dct = @(c) chebtech2.coeffs2vals(c); - C = np.rot90(dct(dct(G.T).T), axis=1) + C = np.rot90(dct(dct(G.T).T)) #, axis=1) - C[0] = .5*C[0] - C[:,1] = .5*C[:, 1] - C[0,-1] = .5*C[0, -1] + C[0] = .5 * C[0] + C[:, 1] = .5 * C[:, 1] + C[0, -1] = .5 * C[0, -1] del C[-1] # Take upper-left triangular part: return np.fliplr(np.triu(np.fliplr(C))) - #C = triu(C(:,end:-1:1)); - #C = C(:,end:-1:1); + # C = triu(C(:,end:-1:1)); + # C = C(:,end:-1:1); def padua_fit2(Pad, fun, *args): N = np.shape(Pad)[1] # recover the degree n from N = (n+1)(n+2)/2 - n = int(round(-3 + np.sqrt(1 + 8 * N)) / 2) + _n = int(round(-3 + np.sqrt(1 + 8 * N)) / 2) C0f = fun(Pad[0], Pad[1], *args) return paduavals2coefs(C0f) - - - def _compute_moments(n): k = np.r_[0:n:2] mom = 2 * np.sqrt(2) / (1 - k ** 2) @@ -449,7 +457,8 @@ def padua_val(X, Y, coefficients, domain=(-1, 1, -1, 1), use_meshgrid=False): Evaluate polynomial in padua form at X, Y. Evaluate the interpolation polynomial defined through its coefficient - matrix coefficients at the target points X(:,1),X(:,2) or at the meshgrid(X1,X2) + matrix coefficients at the target points X(:,1),X(:,2) or at the + meshgrid(X1,X2) Parameters ---------- @@ -469,7 +478,7 @@ def padua_val(X, Y, coefficients, domain=(-1, 1, -1, 1), use_meshgrid=False): ''' X, Y = np.atleast_1d(X, Y) original_shape = X.shape - min, max = np.minimum, np.maximum + min, max = np.minimum, np.maximum # @ReservedAssignment a, b, c, d = domain n = np.shape(coefficients)[1] @@ -481,6 +490,12 @@ def padua_val(X, Y, coefficients, domain=(-1, 1, -1, 1), use_meshgrid=False): TX1[1:n + 1] = TX1[1:n + 1] * np.sqrt(2) TX2[1:n + 1] = TX2[1:n + 1] * np.sqrt(2) if use_meshgrid: - return np.dot(TX1.T, np.dot(coefficients, TX2)).T # eval on meshgrid points - val = np.sum(np.dot(TX1.T, coefficients) * TX2.T, axis=1) # scattered points + # eval on meshgrid points + return np.dot(TX1.T, np.dot(coefficients, TX2)).T + val = np.sum( + np.dot( + TX1.T, + coefficients) * + TX2.T, + axis=1) # scattered points return val.reshape(original_shape)