You cannot select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.

1437 lines
44 KiB
Python

from __future__ import absolute_import, division, print_function
11 years ago
import warnings
import numpy as np
from numpy import pi, sqrt, ones, zeros
11 years ago
from scipy import integrate as intg
import scipy.special.orthogonal as ort
from scipy import special as sp
from scipy.integrate import simps, trapz
8 years ago
from wafo.plotbackend import plotbackend as plt
from wafo.demos import humps
from wafo.misc import dea3
from wafo.dctpack import dct
# from pychebfun import Chebfun
11 years ago
_EPS = np.finfo(float).eps
8 years ago
_NODES_AND_WEIGHTS = {}
11 years ago
__all__ = ['dea3', 'clencurt', 'romberg',
'h_roots', 'j_roots', 'la_roots', 'p_roots', 'qrule',
'gaussq', 'richardson', 'quadgr', 'qdemo']
def _assert(cond, msg):
if not cond:
raise ValueError(msg)
def _assert_warn(cond, msg):
if not cond:
warnings.warn(msg)
8 years ago
def clencurt(fun, a, b, n=5, trace=False):
"""
11 years ago
Numerical evaluation of an integral, Clenshaw-Curtis method.
Parameters
----------
fun : callable
a, b : array-like
Lower and upper integration limit, respectively.
n : integer
defines number of evaluation points (default 5)
Returns
-------
q_val = evaluated integral
11 years ago
tol = Estimate of the approximation error
Notes
-----
CLENCURT approximates the integral of f(x) from a to b
using an 2*n+1 points Clenshaw-Curtis formula.
The error estimate is usually a conservative estimate of the
approximation error.
The integral is exact for polynomials of degree 2*n or less.
Example
-------
>>> import numpy as np
>>> val, err = clencurt(np.exp, 0, 2)
>>> np.allclose(val, np.expm1(2)), err[0] < 1e-10
(True, True)
11 years ago
See also
--------
simpson,
gaussq
References
----------
[1] Goodwin, E.T. (1961),
"Modern Computing Methods",
2nd edition, New yourk: Philosophical Library, pp. 78--79
[2] Clenshaw, C.W. and Curtis, A.R. (1960),
Numerische Matematik, Vol. 2, pp. 197--205
"""
8 years ago
# make sure n_2 is even
n_2 = 2 * int(n)
11 years ago
a, b = np.atleast_1d(a, b)
a_shape = a.shape
8 years ago
a = a.ravel()
b = b.ravel()
11 years ago
8 years ago
a_size = np.prod(a_shape)
11 years ago
8 years ago
s = np.c_[0:n_2 + 1:1]
s_2 = np.c_[0:n_2 + 1:2]
x = np.cos(np.pi * s / n_2) * (b - a) / 2. + (b + a) / 2
11 years ago
if hasattr(fun, '__call__'):
f = fun(x)
else:
8 years ago
x_0 = np.flipud(fun[:, 0])
n_2 = len(x_0) - 1
if abs(x - x_0) > 1e-8:
11 years ago
raise ValueError(
8 years ago
'Input vector x must equal cos(pi*s/n_2)*(b-a)/2+(b+a)/2')
11 years ago
f = np.flipud(fun[:, 1::])
if trace:
plt.plot(x, f, '+')
# using a Gauss-Lobatto variant, i.e., first and last
# term f(a) and f(b) is multiplied with 0.5
f[0, :] = f[0, :] / 2
8 years ago
f[n_2, :] = f[n_2, :] / 2
11 years ago
8 years ago
# x = cos(pi*0:n_2/n_2)
# f = f(x)
#
# N+1
# c(k) = (2/N) sum f''(n)*cos(pi*(2*k-2)*(n-1)/N), 1 <= k <= N/2+1.
# n=1
8 years ago
n = n_2 // 2
11 years ago
fft = np.fft.fft
8 years ago
tmp = np.real(fft(f[:n_2, :], axis=0))
c = 2 / n_2 * (tmp[0:n + 1, :] + np.cos(np.pi * s_2) * f[n_2, :])
11 years ago
c[0, :] = c[0, :] / 2
8 years ago
c[n, :] = c[n, :] / 2
11 years ago
8 years ago
c = c[0:n + 1, :] / ((s_2 - 1) * (s_2 + 1))
q_val = (a - b) * np.sum(c, axis=0)
11 years ago
8 years ago
abserr = (b - a) * np.abs(c[n, :])
11 years ago
8 years ago
if a_size > 1:
11 years ago
abserr = np.reshape(abserr, a_shape)
q_val = np.reshape(q_val, a_shape)
return q_val, abserr
11 years ago
def romberg(fun, a, b, releps=1e-3, abseps=1e-3):
"""
11 years ago
Numerical integration with the Romberg method
Parameters
----------
fun : callable
function to integrate
a, b : real scalars
lower and upper integration limits, respectively.
releps, abseps : scalar, optional
requested relative and absolute error, respectively.
Returns
-------
Q : scalar
value of integral
abserr : scalar
estimated absolute error of integral
ROMBERG approximates the integral of F(X) from A to B
using Romberg's method of integration. The function F
must return a vector of output values if a vector of input values is given.
Example
-------
>>> import numpy as np
>>> [q,err] = romberg(np.sqrt,0,10,0,1e-4)
9 years ago
>>> np.allclose(q, 21.08185107)
True
9 years ago
>>> err[0] < 1e-4
9 years ago
True
"""
11 years ago
h = b - a
h_min = 1.0e-9
11 years ago
# Max size of extrapolation table
table_limit = max(min(np.round(np.log2(h / h_min)), 30), 3)
11 years ago
rom = zeros((2, table_limit))
11 years ago
rom[0, 0] = h * (fun(a) + fun(b)) / 2
ipower = 1
8 years ago
f_p = ones(table_limit) * 4
11 years ago
8 years ago
# q_val1 = 0
q_val2 = 0.
q_val4 = rom[0, 0]
abserr = q_val4
# epstab = zeros(1,decdigs+7)
# newflg = 1
8 years ago
# [res,abserr,epstab,newflg] = dea(newflg,q_val4,abserr,epstab)
11 years ago
two = 1
one = 0
8 years ago
converged = False
for i in range(1, table_limit):
11 years ago
h *= 0.5
8 years ago
u_n5 = np.sum(fun(a + np.arange(1, 2 * ipower, 2) * h)) * h
11 years ago
# trapezoidal approximations
8 years ago
# T2n = 0.5 * (Tn + Un) = 0.5*Tn + u_n5
rom[two, 0] = 0.5 * rom[one, 0] + u_n5
11 years ago
8 years ago
f_p[i] = 4 * f_p[i - 1]
11 years ago
# Richardson extrapolation
for k in range(i):
9 years ago
rom[two, k + 1] = (rom[two, k] +
8 years ago
(rom[two, k] - rom[one, k]) / (f_p[k] - 1))
11 years ago
8 years ago
q_val1 = q_val2
q_val2 = q_val4
q_val4 = rom[two, i]
11 years ago
if 2 <= i:
8 years ago
res, abserr = dea3(q_val1, q_val2, q_val4)
# q_val4 = res
converged = abserr <= max(abseps, releps * abs(res))
if converged:
11 years ago
break
# rom(1,1:i) = rom(2,1:i)
two = one
one = (one + 1) % 2
ipower *= 2
8 years ago
_assert(converged, "Integral did not converge to the required accuracy!")
11 years ago
return res, abserr
def _h_roots_newton(n, releps=3e-14, max_iter=10):
8 years ago
# pim4=0.7511255444649425
pim4 = np.pi ** (-1. / 4)
# The roots are symmetric about the origin, so we have to
# find only half of them.
m = int(np.fix((n + 1) / 2))
# Initial approximations to the roots go into z.
anu = 2.0 * n + 1
rhs = np.arange(3, 4 * m, 4) * np.pi / anu
theta = _get_theta(rhs)
z = sqrt(anu) * np.cos(theta)
8 years ago
p = zeros((3, len(z)))
k_0 = 0
k_p1 = 1
8 years ago
for _i in range(max_iter):
# Newtons method carried out simultaneously on the roots.
8 years ago
p[k_0, :] = 0
p[k_p1, :] = pim4
for j in range(1, n + 1):
# Loop up the recurrence relation to get the Hermite
# polynomials evaluated at z.
8 years ago
k_m1 = k_0
k_0 = k_p1
k_p1 = np.mod(k_p1 + 1, 3)
8 years ago
p[k_p1, :] = (z * sqrt(2 / j) * p[k_0, :] -
sqrt((j - 1) / j) * p[k_m1, :])
8 years ago
# p now contains the desired Hermite polynomials.
# We next compute p_deriv, the derivatives,
# by the relation (4.5.21) using p2, the polynomials
# of one lower order.
8 years ago
p_deriv = sqrt(2 * n) * p[k_0, :]
d_z = p[k_p1, :] / p_deriv
8 years ago
z = z - d_z # Newtons formula.
8 years ago
converged = not np.any(abs(d_z) > releps)
if converged:
break
_assert_warn(converged, 'Newton iteration did not converge!')
8 years ago
weights = 2. / p_deriv ** 2
return _expand_roots(z, weights, n, m)
11 years ago
def h_roots(n, method='newton'):
"""
11 years ago
Returns the roots (x) of the nth order Hermite polynomial,
H_n(x), and weights (w) to use in Gaussian Quadrature over
[-inf,inf] with weighting function exp(-x**2).
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
-------
>>> import numpy as np
>>> x, w = h_roots(10)
>>> np.allclose(np.sum(x*w), -5.2516042729766621e-19)
True
11 years ago
See also
--------
qrule, gaussq
References
----------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
"""
11 years ago
if not method.startswith('n'):
return ort.h_roots(n)
return _h_roots_newton(n)
def _j_roots_newton(n, alpha, beta, releps=3e-14, max_iter=10):
# Initial approximations to the roots go into z.
alfbet = alpha + beta
z = np.cos(np.pi * (np.arange(1, n + 1) - 0.25 + 0.5 * alpha) /
(n + 0.5 * (alfbet + 1)))
8 years ago
p = zeros((3, len(z)))
k_0 = 0
k_p1 = 1
for _i in range(max_iter):
# Newton's method carried out simultaneously on the roots.
tmp = 2 + alfbet
8 years ago
p[k_0, :] = 1
p[k_p1, :] = (alpha - beta + tmp * z) / 2
for j in range(2, n + 1):
# Loop up the recurrence relation to get the Jacobi
# polynomials evaluated at z.
8 years ago
k_m1 = k_0
k_0 = k_p1
k_p1 = np.mod(k_p1 + 1, 3)
a = 2. * j * (j + alfbet) * tmp
tmp = tmp + 2
c = 2 * (j - 1 + alpha) * (j - 1 + beta) * tmp
b = (tmp - 1) * (alpha ** 2 - beta ** 2 + tmp * (tmp - 2) * z)
8 years ago
p[k_p1, :] = (b * p[k_0, :] - c * p[k_m1, :]) / a
8 years ago
# p now contains the desired Jacobi polynomials.
# We next compute p_deriv, the derivatives with a standard
# relation involving the polynomials of one lower order.
8 years ago
p_deriv = ((n * (alpha - beta - tmp * z) * p[k_p1, :] +
2 * (n + alpha) * (n + beta) * p[k_0, :]) /
(tmp * (1 - z ** 2)))
d_z = p[k_p1, :] / p_deriv
z = z - d_z # Newton's formula.
8 years ago
converged = not any(abs(d_z) > releps * abs(z))
if converged:
break
8 years ago
_assert_warn(converged, 'too many iterations in jrule')
11 years ago
x = z # Store the root and the weight.
f = (sp.gammaln(alpha + n) + sp.gammaln(beta + n) -
sp.gammaln(n + 1) - sp.gammaln(alpha + beta + n + 1))
8 years ago
weights = (np.exp(f) * tmp * 2 ** alfbet / (p_deriv * p[k_0, :]))
return x, weights
11 years ago
def j_roots(n, alpha, beta, method='newton'):
"""
11 years ago
Returns the roots of the nth order Jacobi polynomial, P^(alpha,beta)_n(x)
and weights (w) to use in Gaussian Quadrature over [-1,1] with weighting
function (1-x)**alpha (1+x)**beta with alpha,beta > -1.
Parameters
----------
n : integer
number of roots
alpha,beta : scalars
defining shape of Jacobi polynomial
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
--------
>>> [x,w]= j_roots(10,0,0)
>>> sum(x*w)
2.7755575615628914e-16
See also
--------
qrule, gaussq
Reference
---------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
"""
_assert((-1 < alpha) & (-1 < beta),
'alpha and beta must be greater than -1')
11 years ago
if not method.startswith('n'):
return ort.j_roots(n, alpha, beta)
return _j_roots_newton(n, alpha, beta)
11 years ago
def la_roots(n, alpha=0, method='newton'):
"""
11 years ago
Returns the roots (x) of the nth order generalized (associated) Laguerre
polynomial, L^(alpha)_n(x), and weights (w) to use in Gaussian quadrature
over [0,inf] with weighting function exp(-x) x**alpha with alpha > -1.
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Laguerre polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
-------
>>> import numpy as np
>>> [x,w] = h_roots(10)
>>> np.sum(x*w)
1.3352627380516791e-17
11 years ago
See also
--------
qrule, gaussq
References
----------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
"""
_assert(-1 < alpha, 'alpha must be greater than -1')
11 years ago
if not method.startswith('n'):
return ort.la_roots(n, alpha)
return _la_roots_newton(n, alpha)
def _get_theta(rhs):
8 years ago
r_3 = rhs ** (1. / 3)
r_2 = r_3 ** 2
c = [9.084064e-01, 5.214976e-02, 2.579930e-03, 3.986126e-03]
theta = r_3 * (c[0] + r_2 * (c[1] + r_2 * (c[2] + r_2 * c[3])))
return theta
def _la_roots_newton(n, alpha, releps=3e-14, max_iter=10):
# Initial approximations to the roots go into z.
anu = 4.0 * n + 2.0 * alpha + 2.0
rhs = np.arange(4 * n - 1, 2, -4) * np.pi / anu
theta = _get_theta(rhs)
z = anu * np.cos(theta) ** 2
8 years ago
d_z = zeros(len(z))
p = zeros((3, len(z)))
p_previous = zeros((1, len(z)))
p_deriv = zeros((1, len(z)))
k_0 = 0
k_p1 = 1
k = slice(len(z))
8 years ago
for _i in range(max_iter):
# Newton's method carried out simultaneously on the roots.
8 years ago
p[k_0, k] = 0.
p[k_p1, k] = 1.
8 years ago
for j in range(1, n + 1):
# Loop up the recurrence relation to get the Laguerre
# polynomials evaluated at z.
8 years ago
km1 = k_0
k_0 = k_p1
k_p1 = np.mod(k_p1 + 1, 3)
8 years ago
p[k_p1, k] = ((2 * j - 1 + alpha - z[k]) * p[k_0, k] -
(j - 1 + alpha) * p[km1, k]) / j
# end
8 years ago
# p now contains the desired Laguerre polynomials.
# We next compute p_deriv, the derivatives with a standard
# relation involving the polynomials of one lower order.
8 years ago
p_previous[k] = p[k_0, k]
p_deriv[k] = (n * p[k_p1, k] - (n + alpha) * p_previous[k]) / z[k]
8 years ago
d_z[k] = p[k_p1, k] / p_deriv[k]
z[k] = z[k] - d_z[k] # Newton?s formula.
# k = find((abs(d_z) > releps.*z))
8 years ago
converged = not np.any(abs(d_z) > releps)
if converged:
break
8 years ago
_assert_warn(converged, 'too many iterations!')
8 years ago
nodes = z
weights = -np.exp(sp.gammaln(alpha + n) -
sp.gammaln(n)) / (p_deriv * n * p_previous)
return nodes, weights
11 years ago
def _p_roots_newton_start(n):
m = int(np.fix((n + 1) / 2))
8 years ago
t = (np.pi / (4 * n + 2)) * np.arange(3, 4 * m, 4)
a = 1 - (1 - 1 / n) / (8 * n * n)
x = a * np.cos(t)
return m, x
def _p_roots_newton(n, ):
"""
Algorithm given by Davis and Rabinowitz in 'Methods
of Numerical Integration', page 365, Academic Press, 1975.
"""
8 years ago
m, x = _p_roots_newton_start(n)
8 years ago
e_1 = n * (n + 1)
for _j in range(2):
8 years ago
p_km1 = 1
p_k = x
for k in range(2, n + 1):
8 years ago
t_1 = x * p_k
p_kp1 = t_1 - p_km1 - (t_1 - p_km1) / k + t_1
p_km1 = p_k
p_k = p_kp1
den = 1. - x * x
d_1 = n * (p_km1 - x * p_k)
d_pn = d_1 / den
d_2pn = (2. * x * d_pn - e_1 * p_k) / den
d_3pn = (4. * x * d_2pn + (2 - e_1) * d_pn) / den
d_4pn = (6. * x * d_3pn + (6 - e_1) * d_2pn) / den
u = p_k / d_pn
v = d_2pn / d_pn
h = -u * (1 + (.5 * u) * (v + u * (v * v - u * d_3pn / (3 * d_pn))))
p = p_k + h * (d_pn + (.5 * h) * (d_2pn + (h / 3) *
(d_3pn + .25 * h * d_4pn)))
d_p = d_pn + h * (d_2pn + (.5 * h) * (d_3pn + h * d_4pn / 3))
h = h - p / d_p
x = x + h
nodes = -x - h
f_x = d_1 - h * e_1 * (p_k + (h / 2) * (d_pn + (h / 3) *
(d_2pn + (h / 4) *
(d_3pn + (.2 * h) * d_4pn))))
weights = 2 * (1 - nodes ** 2) / (f_x ** 2)
return _expand_roots(nodes, weights, n, m)
def _p_roots_newton1(n, releps=1e-15, max_iter=100):
8 years ago
m, x = _p_roots_newton_start(n)
# Compute the zeros of the N+1 Legendre Polynomial
# using the recursion relation and the Newton-Raphson method
# Legendre-Gauss Polynomials
8 years ago
p = zeros((3, m))
# Derivative of LGP
8 years ago
p_deriv = zeros((m,))
d_x = zeros((m,))
# Compute the zeros of the N+1 Legendre Polynomial
# using the recursion relation and the Newton-Raphson method
# Iterate until new points are uniformly within epsilon of old
# points
k = slice(m)
8 years ago
k_0 = 0
k_p1 = 1
for _ix in range(max_iter):
8 years ago
p[k_0, k] = 1
p[k_p1, k] = x[k]
for j in range(2, n + 1):
k_m1 = k_0
k_0 = k_p1
k_p1 = np.mod(k_0 + 1, 3)
p[k_p1, k] = ((2 * j - 1) * x[k] * p[k_0, k] -
(j - 1) * p[k_m1, k]) / j
p_deriv[k] = n * (p[k_0, k] - x[k] * p[k_p1, k]) / (1 - x[k] ** 2)
d_x[k] = p[k_p1, k] / p_deriv[k]
x[k] = x[k] - d_x[k]
k, = np.nonzero((abs(d_x) > releps * np.abs(x)))
converged = len(k) == 0
if converged:
break
8 years ago
_assert(converged, 'Too many iterations!')
nodes = -x
weights = 2. / ((1 - nodes ** 2) * (p_deriv ** 2))
return _expand_roots(nodes, weights, n, m)
def _expand_roots(x, w, n, m):
if (m + m) > n:
x[m - 1] = 0.0
if not (m + m) == n:
m = m - 1
x = np.hstack((x, -x[m - 1::-1]))
w = np.hstack((w, w[m - 1::-1]))
return x, w
11 years ago
def p_roots(n, method='newton', a=-1, b=1):
"""
11 years ago
Returns the roots (x) of the nth order Legendre polynomial, P_n(x),
8 years ago
and weights to use in Gaussian Quadrature over [-1,1] with weighting
11 years ago
function 1.
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
8 years ago
nodes : ndarray
11 years ago
roots
8 years ago
weights : ndarray
11 years ago
weights
Example
-------
Integral of exp(x) from a = 0 to b = 3 is: exp(3)-exp(0)=
>>> import numpy as np
8 years ago
>>> nodes, weights = p_roots(11, a=0, b=3)
>>> np.allclose(np.sum(np.exp(nodes) * weights), 19.085536923187668)
True
11 years ago
See also
--------
quadg.
References
----------
[1] Davis and Rabinowitz (1975) 'Methods of Numerical Integration',
page 365, Academic Press.
[2] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[3] Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
"""
11 years ago
if not method.startswith('n'):
8 years ago
nodes, weights = ort.p_roots(n)
11 years ago
else:
if method.endswith('1'):
8 years ago
nodes, weights = _p_roots_newton1(n)
11 years ago
else:
8 years ago
nodes, weights = _p_roots_newton(n)
11 years ago
if (a != -1) | (b != 1):
# Linear map from[-1,1] to [a,b]
8 years ago
d_h = (b - a) / 2
nodes = d_h * (nodes + 1) + a
weights = weights * d_h
11 years ago
8 years ago
return nodes, weights
11 years ago
def q5_roots(n):
"""
5 : p(x) = 1/sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 1'st kind
"""
8 years ago
j = np.arange(1, n + 1)
weights = ones(n) * np.pi / n
nodes = np.cos((2 * j - 1) * np.pi / (2 * n))
return nodes, weights
def q6_roots(n):
"""
6 : p(x) = sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 2'nd kind
"""
8 years ago
j = np.arange(1, n + 1)
x_j = j * np.pi / (n + 1)
weights = np.pi / (n + 1) * np.sin(x_j) ** 2
nodes = np.cos(x_j)
return nodes, weights
def q7_roots(n):
"""
7 : p(x) = sqrt((x-a)/(b-x)), a = 0, b = 1
"""
8 years ago
j = np.arange(1, n + 1)
x_j = (j - 0.5) * pi / (2 * n + 1)
nodes = np.cos(x_j) ** 2
weights = 2 * np.pi * nodes / (2 * n + 1)
return nodes, weights
def q8_roots(n):
"""
8 : p(x) = 1/sqrt(b-x), a = 0, b = 1
"""
8 years ago
nodes_1, weights_1 = p_roots(2 * n)
k, = np.where(0 <= nodes_1)
weights = 2 * weights_1[k]
nodes = 1 - nodes_1[k] ** 2
return nodes, weights
def q9_roots(n):
"""
9 : p(x) = sqrt(b-x), a = 0, b = 1
"""
8 years ago
nodes_1, weights_1 = p_roots(2 * n + 1)
k, = np.where(0 < nodes_1)
weights = 2 * nodes_1[k] ** 2 * weights_1[k]
nodes = 1 - nodes_1[k] ** 2
return nodes, weights
11 years ago
def qrule(n, wfun=1, alpha=0, beta=0):
"""
11 years ago
Return nodes and weights for Gaussian quadratures.
Parameters
----------
n : integer
number of base points
wfun : integer
defining the weight function, p(x). (default wfun = 1)
1 : p(x) = 1 a =-1, b = 1 Gauss-Legendre
2 : p(x) = exp(-x^2) a =-inf, b = inf Hermite
3 : p(x) = x^alpha*exp(-x) a = 0, b = inf Laguerre
4 : p(x) = (x-a)^alpha*(b-x)^beta a =-1, b = 1 Jacobi
5 : p(x) = 1/sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 1'st kind
6 : p(x) = sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 2'nd kind
7 : p(x) = sqrt((x-a)/(b-x)), a = 0, b = 1
8 : p(x) = 1/sqrt(b-x), a = 0, b = 1
9 : p(x) = sqrt(b-x), a = 0, b = 1
11 years ago
Returns
-------
bp = base points (abscissas)
wf = weight factors
The Gaussian Quadrature integrates a (2n-1)th order
polynomial exactly and the integral is of the form
b n
Int ( p(x)* F(x) ) dx = Sum ( wf_j* F( bp_j ) )
a j=1
where p(x) is the weight function.
For Jacobi and Laguerre: alpha, beta >-1 (default alpha=beta=0)
Examples:
---------
>>> import numpy as np
# integral of x^2 from a = -1 to b = 1
8 years ago
>>> bp, wf = qrule(10)
>>> np.allclose(sum(bp**2*wf), 0.66666666666666641)
True
8 years ago
# integral of exp(-x**2)*x**2 from a = -inf to b = inf
>>> bp, wf = qrule(10,2)
>>> np.allclose(sum(bp ** 2 * wf), 0.88622692545275772)
True
8 years ago
# integral of (x+1)*(1-x)**2 from a = -1 to b = 1
>>> bp, wf = qrule(10,4,1,2)
>>> np.allclose((bp * wf).sum(), 0.26666666666666755)
True
11 years ago
See also
--------
gaussq
Reference
---------
Abromowitz and Stegun (1954)
(for method 5 to 9)
"""
if wfun == 3: # Generalized Laguerre
return la_roots(n, alpha)
if wfun == 4: # Gauss-Jacobi
return j_roots(n, alpha, beta)
_assert(0 < wfun < 10, 'unknown weight function')
root_fun = [None, p_roots, h_roots, la_roots, j_roots, q5_roots, q6_roots,
q7_roots, q8_roots, q9_roots][wfun]
return root_fun(n)
11 years ago
class _Gaussq(object):
"""
11 years ago
Numerically evaluate integral, Gauss quadrature.
Parameters
----------
fun : callable
a,b : array-like
lower and upper integration limits, respectively.
releps, abseps : real scalars, optional
11 years ago
relative and absolute tolerance, respectively.
(default releps=abseps=1e-3).
11 years ago
wfun : scalar integer, optional
defining the weight function, p(x). (default wfun = 1)
1 : p(x) = 1 a =-1, b = 1 Gauss-Legendre
2 : p(x) = exp(-x^2) a =-inf, b = inf Hermite
3 : p(x) = x^alpha*exp(-x) a = 0, b = inf Laguerre
4 : p(x) = (x-a)^alpha*(b-x)^beta a =-1, b = 1 Jacobi
5 : p(x) = 1/sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 1'st kind
6 : p(x) = sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 2'nd kind
7 : p(x) = sqrt((x-a)/(b-x)), a = 0, b = 1
8 : p(x) = 1/sqrt(b-x), a = 0, b = 1
9 : p(x) = sqrt(b-x), a = 0, b = 1
trace : bool, optional
If non-zero a point plot of the integrand (default False).
gn : scalar integer
number of base points to start the integration with (default 2).
alpha, beta : real scalars, optional
Shape parameters of Laguerre or Jacobi weight function
(alpha,beta>-1) (default alpha=beta=0)
Returns
-------
val : ndarray
evaluated integral
err : ndarray
error estimate, absolute tolerance abs(int-intold)
Notes
-----
GAUSSQ numerically evaluate integral using a Gauss quadrature.
The Quadrature integrates a (2m-1)th order polynomial exactly and the
integral is of the form
b
Int (p(x)* Fun(x)) dx
a
GAUSSQ is vectorized to accept integration limits A, B and
coefficients P1,P2,...Pn, as matrices or scalars and the
result is the common size of A, B and P1,P2,...,Pn.
Examples
---------
integration of x**2 from 0 to 2 and from 1 to 4
>>> import numpy as np
>>> A = [0, 1]
>>> B = [2, 4]
>>> fun = lambda x: x**2
>>> val1, err1 = gaussq(fun,A,B)
>>> np.allclose(val1, [ 2.6666667, 21. ])
True
>>> np.allclose(err1, [ 1.7763568e-15, 1.0658141e-14])
True
11 years ago
Integration of x^2*exp(-x) from zero to infinity:
>>> fun2 = lambda x : np.ones(np.shape(x))
>>> val2, err2 = gaussq(fun2, 0, np.inf, wfun=3, alpha=2)
>>> val3, err3 = gaussq(lambda x: x**2,0, np.inf, wfun=3, alpha=0)
>>> np.allclose(val2, 2), err2[0] < 1e-14
(True, True)
>>> np.allclose(val3, 2), err3[0] < 1e-14
(True, True)
11 years ago
Integrate humps from 0 to 2 and from 1 to 4
>>> val4, err4 = gaussq(humps,A,B)
See also
--------
qrule
gaussq2d
"""
@staticmethod
def _get_dx(wfun, jacob, alpha, beta):
def fun1(x):
return x
if wfun == 4:
8 years ago
d_x = jacob ** (alpha + beta + 1)
11 years ago
else:
8 years ago
d_x = [None, fun1, fun1, fun1, None, lambda x: ones(np.shape(x)),
lambda x: x ** 2, fun1, sqrt,
lambda x: sqrt(x) ** 3][wfun](jacob)
return d_x.ravel()
@staticmethod
8 years ago
def _nodes_and_weights(num_nodes, wfun, alpha, beta):
global _NODES_AND_WEIGHTS
name = 'wfun{:d}_{:d}_{:g}_{:g}'.format(wfun, num_nodes, alpha, beta)
nodes_and_weights = _NODES_AND_WEIGHTS.setdefault(name, [])
if len(nodes_and_weights) == 0:
nodes_and_weights.extend(qrule(num_nodes, wfun, alpha, beta))
nodes, weights = nodes_and_weights
return nodes, weights
def _initialize_trace(self, max_iter):
if self.trace:
self.x_trace = [0] * max_iter
self.y_trace = [0] * max_iter
def _plot_trace(self, x, y):
if self.trace:
self.x_trace.append(x.ravel())
self.y_trace.append(y.ravel())
11 years ago
hfig = plt.plot(x, y, 'r.')
plt.setp(hfig, 'color', 'b')
def _plot_final_trace(self):
if self.trace > 0:
plt.clf()
plt.plot(np.hstack(self.x_trace), np.hstack(self.y_trace), '+')
@staticmethod
8 years ago
def _get_jacob(wfun, a, b):
if wfun in [2, 3]:
8 years ago
jacob = ones((np.size(a), 1))
11 years ago
else:
8 years ago
jacob = (b - a) * 0.5
if wfun in [7, 8, 9]:
8 years ago
jacob *= 2
return jacob
11 years ago
@staticmethod
def _warn(k, a_shape):
8 years ago
n = len(k)
if n > 1:
if n == np.prod(a_shape):
11 years ago
tmptxt = 'All integrals did not converge'
else:
8 years ago
tmptxt = '%d integrals did not converge' % (n, )
tmptxt = tmptxt + '--singularities likely!'
11 years ago
else:
tmptxt = 'Integral did not converge--singularity likely!'
warnings.warn(tmptxt)
@staticmethod
def _initialize(wfun, a, b, args):
args = np.broadcast_arrays(*np.atleast_1d(a, b, *args))
a_shape = args[0].shape
args = [np.reshape(x, (-1, 1)) for x in args]
8 years ago
a_out, b_out = args[:2]
args = args[2:]
if wfun in [2, 3]:
8 years ago
a_out = zeros((a_out.size, 1))
return a_out, b_out, args, a_shape
def __call__(self, fun, a, b, releps=1e-3, abseps=1e-3, alpha=0, beta=0,
wfun=1, trace=False, args=(), max_iter=11):
self.trace = trace
8 years ago
num_nodes = 2
8 years ago
a_0, b_0, args, a_shape = self._initialize(wfun, a, b, args)
8 years ago
jacob = self._get_jacob(wfun, a_0, b_0)
shift = int(wfun in [1, 4, 5, 6])
8 years ago
d_x = self._get_dx(wfun, jacob, alpha, beta)
self._initialize_trace(max_iter)
# Break out of the iteration loop for three reasons:
# 1) the last update is very small (compared to int and to releps)
# 2) There are more than 11 iterations. This should NEVER happen.
8 years ago
dtype = np.result_type(fun((a_0+b_0)*0.5, *args))
n_k = np.prod(a_shape) # # of integrals we have to compute
k = np.arange(n_k)
opts = (n_k, dtype)
val, val_old, abserr = zeros(*opts), ones(*opts), zeros(*opts)
8 years ago
nodes_and_weights = self._nodes_and_weights
for i in range(max_iter):
8 years ago
x_n, weights = nodes_and_weights(num_nodes, wfun, alpha, beta)
x = (x_n + shift) * jacob[k, :] + a_0[k, :]
8 years ago
params = [xi[k, :] for xi in args]
y = fun(x, *params)
self._plot_trace(x, y)
8 years ago
val[k] = np.sum(weights * y, axis=1) * d_x[k] # do the integration
if any(np.isnan(val)):
val[np.isnan(val)] = val_old[np.isnan(val)]
if 1 < i:
abserr[k] = abs(val_old[k] - val[k]) # absolute tolerance
k, = np.where(abserr > np.maximum(abs(releps * val), abseps))
8 years ago
n_k = len(k) # of integrals we have to compute again
if n_k == 0:
break
val_old[k] = val[k]
8 years ago
num_nodes *= 2 # double the # of basepoints and weights
else:
self._warn(k, a_shape)
11 years ago
# make sure int is the same size as the integration limits
val.shape = a_shape
abserr.shape = a_shape
11 years ago
self._plot_final_trace()
return val, abserr
gaussq = _Gaussq()
11 years ago
8 years ago
def richardson(q_val, k):
11 years ago
# license BSD
# Richardson extrapolation with parameter estimation
8 years ago
c = np.real((q_val[k - 1] - q_val[k - 2]) / (q_val[k] - q_val[k - 1])) - 1.
# The lower bound 0.07 admits the singularity x.^-0.9
11 years ago
c = max(c, 0.07)
8 years ago
return q_val[k] + (q_val[k] - q_val[k - 1]) / c
11 years ago
class _Quadgr(object):
def _change_variable_and_integrate(self, fun, a, b, abseps, max_iter):
isreal = np.isreal(a) & np.isreal(b) & ~np.isnan(a) & ~np.isnan(b)
_assert(isreal, 'Infinite intervals must be real.')
integrate = self._integrate
# Change of variable
if np.isfinite(a) & np.isinf(b): # a to inf
val, err = integrate(lambda t: fun(a + t / (1 - t)) / (1 - t) ** 2,
0, 1, abseps, max_iter)
elif np.isinf(a) & np.isfinite(b): # -inf to b
val, err = integrate(lambda t: fun(b + t / (1 + t)) / (1 + t) ** 2,
-1, 0, abseps, max_iter)
else: # -inf to inf
val1, err1 = integrate(lambda t: fun(t / (1 - t)) / (1 - t) ** 2,
0, 1, abseps / 2, max_iter)
val2, err2 = integrate(lambda t: fun(t / (1 + t)) / (1 + t) ** 2,
-1, 0, abseps / 2, max_iter)
val = val1 + val2
err = err1 + err2
return val, err
@staticmethod
def _nodes_and_weights():
# Gauss-Legendre quadrature (12-point)
8 years ago
x = np.asarray(
[0.12523340851146894, 0.36783149899818018, 0.58731795428661748,
0.76990267419430469, 0.9041172563704748, 0.98156063424671924])
8 years ago
w = np.asarray(
[0.24914704581340288, 0.23349253653835478, 0.20316742672306584,
0.16007832854334636, 0.10693932599531818, 0.047175336386511842])
8 years ago
nodes = np.hstack((x, -x))
weights = np.hstack((w, w))
return nodes, weights
@staticmethod
def _get_best_estimate(vals0, vals1, vals2, k):
if k >= 6:
q_v = np.hstack((vals0[k], vals1[k], vals2[k]))
q_w = np.hstack((vals0[k - 1], vals1[k - 1], vals2[k - 1]))
elif k >= 4:
q_v = np.hstack((vals0[k], vals1[k]))
q_w = np.hstack((vals0[k - 1], vals1[k - 1]))
else:
q_v = np.atleast_1d(vals0[k])
q_w = vals0[k - 1]
# Estimate absolute error
errors = np.atleast_1d(abs(q_v - q_w))
j = errors.argmin()
err = errors[j]
q_val = q_v[j]
# if k >= 2: # and not iscomplex:
# _val, err1 = dea3(vals0[k - 2], vals0[k - 1], vals0[k])
return q_val, err
def _integrate(self, fun, a, b, abseps, max_iter):
dtype = np.result_type(fun((a+b)/2), fun((a+b)/4))
# Initiate vectors
val0 = zeros(max_iter, dtype=dtype) # Quadrature
val1 = zeros(max_iter, dtype=dtype) # First Richardson extrapolation
val2 = zeros(max_iter, dtype=dtype) # Second Richardson extrapolation
8 years ago
x_n, weights = self._nodes_and_weights()
n = len(x_n)
# One interval
8 years ago
d_x = (b - a) / 2 # Half interval length
x = (a + b) / 2 + d_x * x_n # Nodes
# Quadrature
8 years ago
val0[0] = d_x * np.sum(weights * fun(x), axis=0)
# Successive bisection of intervals
for k in range(1, max_iter):
# Interval bisection
8 years ago
d_x = d_x / 2
x = np.hstack([x + a, x + b]) / 2
# Quadrature
8 years ago
val0[k] = np.sum(np.sum(np.reshape(fun(x), (-1, n)), axis=0) *
weights, axis=0) * d_x
# Richardson extrapolation
if k >= 5:
val1[k] = richardson(val0, k)
val2[k] = richardson(val1, k)
elif k >= 3:
val1[k] = richardson(val0, k)
8 years ago
q_val, err = self._get_best_estimate(val0, val1, val2, k)
8 years ago
converged = (err < abseps) | ~np.isfinite(q_val)
if converged:
break
_assert_warn(converged, 'Max number of iterations reached without '
'convergence.')
8 years ago
_assert_warn(np.isfinite(q_val),
'Integral approximation is Infinite or NaN.')
# The error estimate should not be zero
8 years ago
err = err + 2 * np.finfo(q_val).eps
return q_val, err
@staticmethod
def _order_limits(a, b):
if np.real(a) > np.real(b):
return b, a, True
return a, b, False
def __call__(self, fun, a, b, abseps=1e-5, max_iter=17):
"""
Gauss-Legendre quadrature with Richardson extrapolation.
8 years ago
[q_val,ERR] = QUADGR(FUN,A,B,TOL) approximates the integral of a function
FUN from A to B with an absolute error tolerance TOL. FUN is a function
8 years ago
handle and must accept vector arguments. TOL is 1e-6 by default. q_val is
the integral approximation and ERR is an estimate of the absolute
error.
QUADGR uses a 12-point Gauss-Legendre quadrature. The error estimate is
based on successive interval bisection. Richardson extrapolation
accelerates the convergence for some integrals, especially integrals
with endpoint singularities.
Examples
--------
>>> import numpy as np
8 years ago
>>> q_val, err = quadgr(np.log,0,1)
>>> q, err = quadgr(np.exp,0,9999*1j*np.pi)
>>> np.allclose(q, -2.0000000000122662), err < 1.0e-08
(True, True)
>>> q, err = quadgr(lambda x: np.sqrt(4-x**2), 0, 2, abseps=1e-12)
>>> np.allclose(q, 3.1415926535897811), err < 1.0e-12
(True, True)
>>> q, err = quadgr(lambda x: x**-0.75, 0, 1)
>>> np.allclose(q, 4), err < 1.e-13
(True, True)
>>> q, err = quadgr(lambda x: 1./np.sqrt(1-x**2), -1, 1)
>>> np.allclose(q, 3.141596056985029), err < 1.0e-05
(True, True)
>>> q, err = quadgr(lambda x: np.exp(-x**2), -np.inf, np.inf, 1e-9)
>>> np.allclose(q, np.sqrt(np.pi)), err < 1e-9
(True, True)
>>> q, err = quadgr(lambda x: np.cos(x)*np.exp(-x), 0, np.inf, 1e-9)
>>> np.allclose(q, 0.5), err < 1e-9
(True, True)
See also
--------
QUAD,
QUADGK
"""
# Author: jonas.lundgren@saabgroup.com, 2009. license BSD
# Order limits (required if infinite limits)
a = np.asarray(a)
b = np.asarray(b)
if a == b:
8 years ago
q_val = b - a
err = b - a
8 years ago
return q_val, err
a, b, reverse = self._order_limits(a, b)
improper_integral = np.isinf(a) | np.isinf(b)
8 years ago
if improper_integral: # Infinite limits
q_val, err = self._change_variable_and_integrate(fun, a, b, abseps,
max_iter)
else:
8 years ago
q_val, err = self._integrate(fun, a, b, abseps, max_iter)
11 years ago
# Reverse direction
if reverse:
8 years ago
q_val = -q_val
11 years ago
8 years ago
return q_val, err
11 years ago
quadgr = _Quadgr()
11 years ago
def boole(y, x):
a, b = x[0], x[-1]
n = len(x)
h = (b - a) / (n - 1)
return (2 * h / 45) * (7 * (y[0] + y[-1]) + 12 * np.sum(y[2:n - 1:4]) +
32 * np.sum(y[1:n - 1:2]) +
14 * np.sum(y[4:n - 3:4]))
def _display(neval, vals_dic, err_dic, plot_error):
# display results
kmax = len(neval)
names = sorted(vals_dic.keys())
num_cols = 2
formats = ['%4.0f, '] + ['%10.10f, '] * num_cols * 2
formats[-1] = formats[-1].split(',')[0]
formats_h = ['%4s, '] + ['%20s, '] * num_cols
formats_h[-1] = formats_h[-1].split(',')[0]
headers = ['evals'] + ['%12s %12s' % ('approx', 'error')] * num_cols
while len(names) > 0:
print(''.join(fi % t for (fi, t) in zip(formats_h,
['ftn'] + names[:num_cols])))
print(' '.join(headers))
data = [neval]
for name in names[:num_cols]:
data.append(vals_dic[name])
data.append(err_dic[name])
data = np.vstack(tuple(data)).T
for k in range(kmax):
tmp = data[k].tolist()
print(''.join(fi % t for (fi, t) in zip(formats, tmp)))
if plot_error:
plt.figure(0)
for name in names[:num_cols]:
plt.loglog(neval, err_dic[name], label=name)
names = names[num_cols:]
if plot_error:
plt.xlabel('number of function evaluations')
plt.ylabel('error')
plt.legend()
plt.show('hold')
def qdemo(f, a, b, kmax=9, plot_error=False):
"""
11 years ago
Compares different quadrature rules.
Parameters
----------
f : callable
function
a,b : scalars
lower and upper integration limits
Details
-------
qdemo(f,a,b) computes and compares various approximations to
the integral of f from a to b. Three approximations are used,
the composite trapezoid, Simpson's, and Boole's rules, all with
equal length subintervals.
In a case like qdemo(exp,0,3) one can see the expected
convergence rates for each of the three methods.
In a case like qdemo(sqrt,0,3), the convergence rate is limited
not by the method, but by the singularity of the integrand.
Example
-------
>>> import numpy as np
>>> qdemo(np.exp,0,3)
true value = 19.08553692
ftn, Boole, Chebychev
evals approx error approx error
3, 19.4008539142, 0.3153169910, 19.5061466023, 0.4206096791
5, 19.0910191534, 0.0054822302, 19.0910191534, 0.0054822302
9, 19.0856414320, 0.0001045088, 19.0855374134, 0.0000004902
17, 19.0855386464, 0.0000017232, 19.0855369232, 0.0000000000
33, 19.0855369505, 0.0000000273, 19.0855369232, 0.0000000000
65, 19.0855369236, 0.0000000004, 19.0855369232, 0.0000000000
129, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
257, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
513, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
ftn, Clenshaw-Curtis, Gauss-Legendre
evals approx error approx error
3, 19.5061466023, 0.4206096791, 19.0803304585, 0.0052064647
5, 19.0834145766, 0.0021223465, 19.0855365951, 0.0000003281
9, 19.0855369150, 0.0000000082, 19.0855369232, 0.0000000000
17, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
33, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
65, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
129, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
257, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
513, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
ftn, Simps, Trapz
evals approx error approx error
3, 19.5061466023, 0.4206096791, 22.5366862979, 3.4511493747
5, 19.1169646189, 0.0314276957, 19.9718950387, 0.8863581155
9, 19.0875991312, 0.0020622080, 19.3086731081, 0.2231361849
17, 19.0856674267, 0.0001305035, 19.1414188470, 0.0558819239
33, 19.0855451052, 0.0000081821, 19.0995135407, 0.0139766175
65, 19.0855374350, 0.0000005118, 19.0890314614, 0.0034945382
129, 19.0855369552, 0.0000000320, 19.0864105817, 0.0008736585
257, 19.0855369252, 0.0000000020, 19.0857553393, 0.0002184161
513, 19.0855369233, 0.0000000001, 19.0855915273, 0.0000546041
"""
11 years ago
true_val, _tol = intg.quad(f, a, b)
print('true value = %12.8f' % (true_val,))
neval = zeros(kmax, dtype=int)
vals_dic = {}
err_dic = {}
11 years ago
# try various approximations
methods = [trapz, simps, boole, ]
11 years ago
for k in range(kmax):
11 years ago
n = 2 ** (k + 1) + 1
neval[k] = n
x = np.linspace(a, b, n)
y = f(x)
for method in methods:
name = method.__name__.title()
q = method(y, x)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
name = 'Clenshaw-Curtis'
q = clencurt(f, a, b, (n - 1) // 2)[0]
vals_dic.setdefault(name, []).append(q[0])
err_dic.setdefault(name, []).append(abs(q[0] - true_val))
name = 'Chebychev'
8 years ago
c_k = np.polynomial.chebyshev.chebfit(x, y, deg=min(n-1, 36))
c_ki = np.polynomial.chebyshev.chebint(c_k)
q = np.polynomial.chebyshev.chebval(x[-1], c_ki)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
8 years ago
# c_k = chebfit(f,n,a,b)
# q = chebval(b,chebint(c_k,a,b),a,b)
# qc2[k] = q; ec2[k] = abs(q - true)
name = 'Gauss-Legendre' # quadrature
11 years ago
q = intg.fixed_quad(f, a, b, n=n)[0]
# [x, w]=qrule(n,1)
11 years ago
# x = (b-a)/2*x + (a+b)/2 % Transform base points X.
# w = (b-a)/2*w % Adjust weigths.
# q = sum(feval(f,x)*w)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
11 years ago
_display(neval, vals_dic, err_dic, plot_error)
11 years ago
def main():
# val, err = clencurt(np.exp, 0, 2)
# valt = np.exp(2) - np.exp(0)
# [Q, err] = quadgr(lambda x: x ** 2, 1, 4, 1e-9)
# [Q, err] = quadgr(humps, 1, 4, 1e-9)
#
# [x, w] = h_roots(11, 'newton')
# sum(w)
# [x2, w2] = la_roots(11, 1, 't')
#
# from scitools import numpyutils as npu #@UnresolvedImport
# fun = npu.wrap2callable('x**2')
# p0 = fun(0)
# A = [0, 1, 1]; B = [2, 4, 3]
# area, err = gaussq(fun, A, B)
#
# fun = npu.wrap2callable('x**2')
# [val1, err1] = gaussq(fun, A, B)
#
#
# Integration of x^2*exp(-x) from zero to infinity:
# fun2 = npu.wrap2callable('1')
# [val2, err2] = gaussq(fun2, 0, np.inf, wfun=3, alpha=2)
# [val2, err2] = gaussq(lambda x: x ** 2, 0, np.inf, wfun=3, alpha=0)
#
# Integrate humps from 0 to 2 and from 1 to 4
# [val3, err3] = gaussq(humps, A, B)
#
# [x, w] = p_roots(11, 'newton', 1, 3)
# y = np.sum(x ** 2 * w)
11 years ago
x = np.linspace(0, np.pi / 2)
_q0 = np.trapz(humps(x), x)
[q, err] = romberg(humps, 0, np.pi / 2, 1e-4)
print(q, err)
11 years ago
if __name__ == '__main__':
from wafo.testing import test_docstrings
test_docstrings(__file__)
# qdemo(np.exp, 0, 3, plot_error=True)
# plt.show('hold')
11 years ago
# main()