You cannot select more than 25 topics Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.

1361 lines
42 KiB
Python

from __future__ import absolute_import, division
11 years ago
import warnings
import numpy as np
from numpy import pi, sqrt, ones, zeros # @UnresolvedImport
from scipy import integrate as intg
import scipy.special.orthogonal as ort
from scipy import special as sp
from .plotbackend import plotbackend as plt
from scipy.integrate import simps, trapz
from .demos import humps
from .misc import dea3
from .dctpack import dct
# from pychebfun import Chebfun
11 years ago
_EPS = np.finfo(float).eps
11 years ago
_POINTS_AND_WEIGHTS = {}
__all__ = ['dea3', 'clencurt', 'romberg',
'h_roots', 'j_roots', 'la_roots', 'p_roots', 'qrule',
'gaussq', 'richardson', 'quadgr', 'qdemo']
def clencurt(fun, a, b, n0=5, trace=False, args=()):
11 years ago
'''
Numerical evaluation of an integral, Clenshaw-Curtis method.
Parameters
----------
fun : callable
a, b : array-like
Lower and upper integration limit, respectively.
n : integer
defines number of evaluation points (default 5)
Returns
-------
Q = evaluated integral
tol = Estimate of the approximation error
Notes
-----
CLENCURT approximates the integral of f(x) from a to b
using an 2*n+1 points Clenshaw-Curtis formula.
The error estimate is usually a conservative estimate of the
approximation error.
The integral is exact for polynomials of degree 2*n or less.
Example
-------
>>> import numpy as np
>>> val,err = clencurt(np.exp,0,2)
>>> abs(val-np.expm1(2))< err, err<1e-10
(array([ True], dtype=bool), array([ True], dtype=bool))
See also
--------
simpson,
gaussq
References
----------
[1] Goodwin, E.T. (1961),
"Modern Computing Methods",
2nd edition, New yourk: Philosophical Library, pp. 78--79
[2] Clenshaw, C.W. and Curtis, A.R. (1960),
Numerische Matematik, Vol. 2, pp. 197--205
'''
# make sure n is even
11 years ago
n = 2 * n0
a, b = np.atleast_1d(a, b)
a_shape = a.shape
af = a.ravel()
bf = b.ravel()
Na = np.prod(a_shape)
s = np.r_[0:n + 1]
s2 = np.r_[0:n + 1:2]
s2.shape = (-1, 1)
x1 = np.cos(np.pi * s / n)
x1.shape = (-1, 1)
x = x1 * (bf - af) / 2. + (bf + af) / 2
if hasattr(fun, '__call__'):
f = fun(x)
else:
x0 = np.flipud(fun[:, 0])
n = len(x0) - 1
if abs(x - x0) > 1e-8:
raise ValueError(
'Input vector x must equal cos(pi*s/n)*(b-a)/2+(b+a)/2')
f = np.flipud(fun[:, 1::])
if trace:
plt.plot(x, f, '+')
# using a Gauss-Lobatto variant, i.e., first and last
# term f(a) and f(b) is multiplied with 0.5
f[0, :] = f[0, :] / 2
f[n, :] = f[n, :] / 2
# % x = cos(pi*0:n/n)
# % f = f(x)
# %
# % N+1
# % c(k) = (2/N) sum f''(n)*cos(pi*(2*k-2)*(n-1)/N), 1 <= k <= N/2+1.
# % n=1
fft = np.fft.fft
tmp = np.real(fft(f[:n, :], axis=0))
c = 2 / n * (tmp[0:n / 2 + 1, :] + np.cos(np.pi * s2) * f[n, :])
c[0, :] = c[0, :] / 2
c[n / 2, :] = c[n / 2, :] / 2
# % alternative call
# c2 = dct(f)
11 years ago
c = c[0:n / 2 + 1, :] / ((s2 - 1) * (s2 + 1))
Q = (af - bf) * np.sum(c, axis=0)
# Q = (a-b).*sum( c(1:n/2+1,:)./repmat((s2-1).*(s2+1),1,Na))
abserr = (bf - af) * np.abs(c[n / 2, :])
if Na > 1:
abserr = np.reshape(abserr, a_shape)
Q = np.reshape(Q, a_shape)
return Q, abserr
def romberg(fun, a, b, releps=1e-3, abseps=1e-3):
'''
Numerical integration with the Romberg method
Parameters
----------
fun : callable
function to integrate
a, b : real scalars
lower and upper integration limits, respectively.
releps, abseps : scalar, optional
requested relative and absolute error, respectively.
Returns
-------
Q : scalar
value of integral
abserr : scalar
estimated absolute error of integral
ROMBERG approximates the integral of F(X) from A to B
using Romberg's method of integration. The function F
must return a vector of output values if a vector of input values is given.
Example
-------
>>> import numpy as np
>>> [q,err] = romberg(np.sqrt,0,10,0,1e-4)
>>> q,err
(array([ 21.0818511]), array([ 6.6163547e-05]))
'''
h = b - a
hMin = 1.0e-9
# Max size of extrapolation table
tableLimit = max(min(np.round(np.log2(h / hMin)), 30), 3)
rom = zeros((2, tableLimit))
rom[0, 0] = h * (fun(a) + fun(b)) / 2
ipower = 1
fp = ones(tableLimit) * 4
# Ih1 = 0
11 years ago
Ih2 = 0.
Ih4 = rom[0, 0]
abserr = Ih4
# epstab = zeros(1,decdigs+7)
# newflg = 1
# [res,abserr,epstab,newflg] = dea(newflg,Ih4,abserr,epstab)
11 years ago
two = 1
one = 0
for i in range(1, tableLimit):
11 years ago
h *= 0.5
Un5 = np.sum(fun(a + np.arange(1, 2 * ipower, 2) * h)) * h
# trapezoidal approximations
# T2n = 0.5 * (Tn + Un) = 0.5*Tn + Un5
rom[two, 0] = 0.5 * rom[one, 0] + Un5
fp[i] = 4 * fp[i - 1]
# Richardson extrapolation
for k in range(i):
9 years ago
rom[two, k + 1] = (rom[two, k] +
(rom[two, k] - rom[one, k]) / (fp[k] - 1))
11 years ago
Ih1 = Ih2
Ih2 = Ih4
Ih4 = rom[two, i]
if (2 <= i):
res, abserr = dea3(Ih1, Ih2, Ih4)
11 years ago
# Ih4 = res
if (abserr <= max(abseps, releps * abs(res))):
break
# rom(1,1:i) = rom(2,1:i)
two = one
one = (one + 1) % 2
ipower *= 2
return res, abserr
def h_roots(n, method='newton'):
'''
Returns the roots (x) of the nth order Hermite polynomial,
H_n(x), and weights (w) to use in Gaussian Quadrature over
[-inf,inf] with weighting function exp(-x**2).
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
-------
>>> import numpy as np
>>> [x,w] = h_roots(10)
>>> np.sum(x*w)
-5.2516042729766621e-19
See also
--------
qrule, gaussq
References
----------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
'''
if not method.startswith('n'):
return ort.h_roots(n)
else:
sqrt = np.sqrt
max_iter = 10
releps = 3e-14
C = [9.084064e-01, 5.214976e-02, 2.579930e-03, 3.986126e-03]
# PIM4=0.7511255444649425
PIM4 = np.pi ** (-1. / 4)
# The roots are symmetric about the origin, so we have to
# find only half of them.
m = int(np.fix((n + 1) / 2))
# Initial approximations to the roots go into z.
anu = 2.0 * n + 1
rhs = np.arange(3, 4 * m, 4) * np.pi / anu
r3 = rhs ** (1. / 3)
r2 = r3 ** 2
theta = r3 * (C[0] + r2 * (C[1] + r2 * (C[2] + r2 * C[3])))
z = sqrt(anu) * np.cos(theta)
L = zeros((3, len(z)))
k0 = 0
kp1 = 1
for _its in range(max_iter):
11 years ago
# Newtons method carried out simultaneously on the roots.
L[k0, :] = 0
L[kp1, :] = PIM4
for j in range(1, n + 1):
# Loop up the recurrence relation to get the Hermite
# polynomials evaluated at z.
11 years ago
km1 = k0
k0 = kp1
kp1 = np.mod(kp1 + 1, 3)
L[kp1, :] = (z * sqrt(2 / j) * L[k0, :] -
np.sqrt((j - 1) / j) * L[km1, :])
# L now contains the desired Hermite polynomials.
# We next compute pp, the derivatives,
# by the relation (4.5.21) using p2, the polynomials
# of one lower order.
pp = sqrt(2 * n) * L[k0, :]
dz = L[kp1, :] / pp
z = z - dz # Newtons formula.
if not np.any(abs(dz) > releps):
break
else:
warnings.warn('too many iterations!')
x = np.empty(n)
w = np.empty(n)
x[0:m] = z # Store the root
x[n - 1:n - m - 1:-1] = -z # and its symmetric counterpart.
w[0:m] = 2. / pp ** 2 # Compute the weight
w[n - 1:n - m - 1:-1] = w[0:m] # and its symmetric counterpart.
return x, w
def j_roots(n, alpha, beta, method='newton'):
'''
Returns the roots of the nth order Jacobi polynomial, P^(alpha,beta)_n(x)
and weights (w) to use in Gaussian Quadrature over [-1,1] with weighting
function (1-x)**alpha (1+x)**beta with alpha,beta > -1.
Parameters
----------
n : integer
number of roots
alpha,beta : scalars
defining shape of Jacobi polynomial
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
--------
>>> [x,w]= j_roots(10,0,0)
>>> sum(x*w)
2.7755575615628914e-16
See also
--------
qrule, gaussq
Reference
---------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
'''
if not method.startswith('n'):
[x, w] = ort.j_roots(n, alpha, beta)
else:
max_iter = 10
releps = 3e-14
# Initial approximations to the roots go into z.
alfbet = alpha + beta
z = np.cos(np.pi * (np.arange(1, n + 1) - 0.25 + 0.5 * alpha) /
(n + 0.5 * (alfbet + 1)))
L = zeros((3, len(z)))
k0 = 0
kp1 = 1
for _its in range(max_iter):
11 years ago
# Newton's method carried out simultaneously on the roots.
tmp = 2 + alfbet
L[k0, :] = 1
L[kp1, :] = (alpha - beta + tmp * z) / 2
for j in range(2, n + 1):
11 years ago
# Loop up the recurrence relation to get the Jacobi
# polynomials evaluated at z.
km1 = k0
k0 = kp1
kp1 = np.mod(kp1 + 1, 3)
a = 2. * j * (j + alfbet) * tmp
tmp = tmp + 2
c = 2 * (j - 1 + alpha) * (j - 1 + beta) * tmp
b = (tmp - 1) * (alpha ** 2 - beta ** 2 + tmp * (tmp - 2) * z)
L[kp1, :] = (b * L[k0, :] - c * L[km1, :]) / a
# L now contains the desired Jacobi polynomials.
# We next compute pp, the derivatives with a standard
# relation involving the polynomials of one lower order.
pp = ((n * (alpha - beta - tmp * z) * L[kp1, :] +
2 * (n + alpha) * (n + beta) * L[k0, :]) /
(tmp * (1 - z ** 2)))
11 years ago
dz = L[kp1, :] / pp
z = z - dz # Newton's formula.
if not any(abs(dz) > releps * abs(z)):
break
else:
warnings.warn('too many iterations in jrule')
x = z # %Store the root and the weight.
f = (sp.gammaln(alpha + n) + sp.gammaln(beta + n) -
sp.gammaln(n + 1) - sp.gammaln(alpha + beta + n + 1))
w = (np.exp(f) * tmp * 2 ** alfbet / (pp * L[k0, :]))
return x, w
def la_roots(n, alpha=0, method='newton'):
'''
Returns the roots (x) of the nth order generalized (associated) Laguerre
polynomial, L^(alpha)_n(x), and weights (w) to use in Gaussian quadrature
over [0,inf] with weighting function exp(-x) x**alpha with alpha > -1.
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Laguerre polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
-------
>>> import numpy as np
>>> [x,w] = h_roots(10)
>>> np.sum(x*w)
-5.2516042729766621e-19
See also
--------
qrule, gaussq
References
----------
[1] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[2]. Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
'''
if alpha <= -1:
raise ValueError('alpha must be greater than -1')
if not method.startswith('n'):
return ort.la_roots(n, alpha)
else:
max_iter = 10
releps = 3e-14
C = [9.084064e-01, 5.214976e-02, 2.579930e-03, 3.986126e-03]
# Initial approximations to the roots go into z.
anu = 4.0 * n + 2.0 * alpha + 2.0
rhs = np.arange(4 * n - 1, 2, -4) * np.pi / anu
r3 = rhs ** (1. / 3)
r2 = r3 ** 2
theta = r3 * (C[0] + r2 * (C[1] + r2 * (C[2] + r2 * C[3])))
z = anu * np.cos(theta) ** 2
dz = zeros(len(z))
L = zeros((3, len(z)))
Lp = zeros((1, len(z)))
pp = zeros((1, len(z)))
k0 = 0
kp1 = 1
k = slice(len(z))
for _its in range(max_iter):
# Newton's method carried out simultaneously on the roots.
11 years ago
L[k0, k] = 0.
L[kp1, k] = 1.
for jj in range(1, n + 1):
11 years ago
# Loop up the recurrence relation to get the Laguerre
# polynomials evaluated at z.
km1 = k0
k0 = kp1
kp1 = np.mod(kp1 + 1, 3)
L[kp1, k] = ((2 * jj - 1 + alpha - z[k]) * L[
k0, k] - (jj - 1 + alpha) * L[km1, k]) / jj
# end
# L now contains the desired Laguerre polynomials.
# We next compute pp, the derivatives with a standard
# relation involving the polynomials of one lower order.
11 years ago
Lp[k] = L[k0, k]
pp[k] = (n * L[kp1, k] - (n + alpha) * Lp[k]) / z[k]
dz[k] = L[kp1, k] / pp[k]
z[k] = z[k] - dz[k] # % Newton?s formula.
# k = find((abs(dz) > releps.*z))
11 years ago
if not np.any(abs(dz) > releps):
break
else:
warnings.warn('too many iterations!')
x = z
w = -np.exp(sp.gammaln(alpha + n) - sp.gammaln(n)) / (pp * n * Lp)
return x, w
def p_roots(n, method='newton', a=-1, b=1):
'''
Returns the roots (x) of the nth order Legendre polynomial, P_n(x),
and weights (w) to use in Gaussian Quadrature over [-1,1] with weighting
function 1.
Parameters
----------
n : integer
number of roots
method : 'newton' or 'eigenvalue'
uses Newton Raphson to find zeros of the Hermite polynomial (Fast)
or eigenvalue of the jacobi matrix (Slow) to obtain the nodes and
weights, respectively.
Returns
-------
x : ndarray
roots
w : ndarray
weights
Example
-------
Integral of exp(x) from a = 0 to b = 3 is: exp(3)-exp(0)=
>>> import numpy as np
>>> [x,w] = p_roots(11,a=0,b=3)
>>> np.sum(np.exp(x)*w)
19.085536923187668
See also
--------
quadg.
References
----------
[1] Davis and Rabinowitz (1975) 'Methods of Numerical Integration',
page 365, Academic Press.
[2] Golub, G. H. and Welsch, J. H. (1969)
'Calculation of Gaussian Quadrature Rules'
Mathematics of Computation, vol 23,page 221-230,
[3] Stroud and Secrest (1966), 'gaussian quadrature formulas',
prentice-hall, Englewood cliffs, n.j.
'''
if not method.startswith('n'):
x, w = ort.p_roots(n)
else:
m = int(np.fix((n + 1) / 2))
mm = 4 * m - 1
t = (np.pi / (4 * n + 2)) * np.arange(3, mm + 1, 4)
nn = (1 - (1 - 1 / n) / (8 * n * n))
xo = nn * np.cos(t)
if method.endswith('1'):
# Compute the zeros of the N+1 Legendre Polynomial
# using the recursion relation and the Newton-Raphson method
# Legendre-Gauss Polynomials
L = zeros((3, m))
# Derivative of LGP
Lp = zeros((m,))
dx = zeros((m,))
releps = 1e-15
max_iter = 100
# Compute the zeros of the N+1 Legendre Polynomial
# using the recursion relation and the Newton-Raphson method
# Iterate until new points are uniformly within epsilon of old
# points
k = slice(m)
k0 = 0
kp1 = 1
for _ix in range(max_iter):
11 years ago
L[k0, k] = 1
L[kp1, k] = xo[k]
for jj in range(2, n + 1):
11 years ago
km1 = k0
k0 = kp1
kp1 = np.mod(k0 + 1, 3)
L[kp1, k] = ((2 * jj - 1) * xo[k] * L[
k0, k] - (jj - 1) * L[km1, k]) / jj
Lp[k] = n * (L[k0, k] - xo[k] * L[kp1, k]) / (1 - xo[k] ** 2)
dx[k] = L[kp1, k] / Lp[k]
xo[k] = xo[k] - dx[k]
k, = np.nonzero((abs(dx) > releps * np.abs(xo)))
if len(k) == 0:
break
else:
warnings.warn('Too many iterations!')
x = -xo
w = 2. / ((1 - x ** 2) * (Lp ** 2))
else:
# Algorithm given by Davis and Rabinowitz in 'Methods
# of Numerical Integration', page 365, Academic Press, 1975.
e1 = n * (n + 1)
for _j in range(2):
11 years ago
pkm1 = 1
pk = xo
for k in range(2, n + 1):
11 years ago
t1 = xo * pk
pkp1 = t1 - pkm1 - (t1 - pkm1) / k + t1
pkm1 = pk
pk = pkp1
den = 1. - xo * xo
d1 = n * (pkm1 - xo * pk)
dpn = d1 / den
d2pn = (2. * xo * dpn - e1 * pk) / den
d3pn = (4. * xo * d2pn + (2 - e1) * dpn) / den
d4pn = (6. * xo * d3pn + (6 - e1) * d2pn) / den
u = pk / dpn
v = d2pn / dpn
h = (-u * (1 + (.5 * u) * (v + u *
(v * v - u * d3pn / (3 * dpn)))))
p = (pk + h * (dpn + (.5 * h) * (d2pn + (h / 3) *
(d3pn + .25 * h * d4pn))))
dp = dpn + h * (d2pn + (.5 * h) * (d3pn + h * d4pn / 3))
h = h - p / dp
xo = xo + h
x = -xo - h
fx = (d1 - h * e1 * (pk + (h / 2) *
(dpn + (h / 3) * (d2pn + (h / 4) *
(d3pn + (.2 * h) * d4pn)))))
w = 2 * (1 - x ** 2) / (fx ** 2)
if (m + m) > n:
x[m - 1] = 0.0
if not ((m + m) == n):
m = m - 1
x = np.hstack((x, -x[m - 1::-1]))
w = np.hstack((w, w[m - 1::-1]))
if (a != -1) | (b != 1):
# Linear map from[-1,1] to [a,b]
dh = (b - a) / 2
x = dh * (x + 1) + a
w = w * dh
return x, w
def qrule(n, wfun=1, alpha=0, beta=0):
'''
Return nodes and weights for Gaussian quadratures.
Parameters
----------
n : integer
number of base points
wfun : integer
defining the weight function, p(x). (default wfun = 1)
1,11,21: p(x) = 1 a =-1, b = 1 Gauss-Legendre
2,12 : p(x) = exp(-x^2) a =-inf, b = inf Hermite
3,13 : p(x) = x^alpha*exp(-x) a = 0, b = inf Laguerre
4,14 : p(x) = (x-a)^alpha*(b-x)^beta a =-1, b = 1 Jacobi
5 : p(x) = 1/sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 1'st kind
6 : p(x) = sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 2'nd kind
7 : p(x) = sqrt((x-a)/(b-x)), a = 0, b = 1
8 : p(x) = 1/sqrt(b-x), a = 0, b = 1
9 : p(x) = sqrt(b-x), a = 0, b = 1
11 years ago
Returns
-------
bp = base points (abscissas)
wf = weight factors
The Gaussian Quadrature integrates a (2n-1)th order
polynomial exactly and the integral is of the form
b n
Int ( p(x)* F(x) ) dx = Sum ( wf_j* F( bp_j ) )
a j=1
where p(x) is the weight function.
For Jacobi and Laguerre: alpha, beta >-1 (default alpha=beta=0)
Examples:
---------
>>> [bp,wf] = qrule(10)
>>> sum(bp**2*wf) # integral of x^2 from a = -1 to b = 1
0.66666666666666641
>>> [bp,wf] = qrule(10,2)
>>> sum(bp**2*wf) # integral of exp(-x.^2)*x.^2 from a = -inf to b = inf
0.88622692545275772
>>> [bp,wf] = qrule(10,4,1,2)
>>> (bp*wf).sum() # integral of (x+1)*(1-x)^2 from a = -1 to b = 1
0.26666666666666755
See also
--------
gaussq
Reference
---------
Abromowitz and Stegun (1954)
(for method 5 to 9)
'''
if (alpha <= -1) | (beta <= -1):
raise ValueError('alpha and beta must be greater than -1')
if wfun == 1: # Gauss-Legendre
[bp, wf] = p_roots(n)
elif wfun == 2: # Hermite
[bp, wf] = h_roots(n)
elif wfun == 3: # Generalized Laguerre
[bp, wf] = la_roots(n, alpha)
elif wfun == 4: # Gauss-Jacobi
[bp, wf] = j_roots(n, alpha, beta)
elif wfun == 5: # p(x)=1/sqrt((x-a)*(b-x)), a=-1 and b=1 (default)
jj = np.arange(1, n + 1)
wf = ones(n) * np.pi / n
bp = np.cos((2 * jj - 1) * np.pi / (2 * n))
elif wfun == 6: # p(x)=sqrt((x-a)*(b-x)), a=-1 and b=1
jj = np.arange(1, n + 1)
xj = jj * np.pi / (n + 1)
wf = np.pi / (n + 1) * np.sin(xj) ** 2
bp = np.cos(xj)
elif wfun == 7: # p(x)=sqrt((x-a)/(b-x)), a=0 and b=1
jj = np.arange(1, n + 1)
xj = (jj - 0.5) * pi / (2 * n + 1)
bp = np.cos(xj) ** 2
wf = 2 * np.pi * bp / (2 * n + 1)
elif wfun == 8: # p(x)=1/sqrt(b-x), a=0 and b=1
[bp1, wf1] = p_roots(2 * n)
k, = np.where(0 <= bp1)
wf = 2 * wf1[k]
bp = 1 - bp1[k] ** 2
elif wfun == 9: # p(x)=np.sqrt(b-x), a=0 and b=1
[bp1, wf1] = p_roots(2 * n + 1)
k, = np.where(0 < bp1)
wf = 2 * bp1[k] ** 2 * wf1[k]
bp = 1 - bp1[k] ** 2
else:
raise ValueError('unknown weight function')
return bp, wf
class _Gaussq(object):
11 years ago
'''
Numerically evaluate integral, Gauss quadrature.
Parameters
----------
fun : callable
a,b : array-like
lower and upper integration limits, respectively.
releps, abseps : real scalars, optional
11 years ago
relative and absolute tolerance, respectively.
(default releps=abseps=1e-3).
11 years ago
wfun : scalar integer, optional
defining the weight function, p(x). (default wfun = 1)
1 : p(x) = 1 a =-1, b = 1 Gauss-Legendre
2 : p(x) = exp(-x^2) a =-inf, b = inf Hermite
3 : p(x) = x^alpha*exp(-x) a = 0, b = inf Laguerre
4 : p(x) = (x-a)^alpha*(b-x)^beta a =-1, b = 1 Jacobi
5 : p(x) = 1/sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 1'st kind
6 : p(x) = sqrt((x-a)*(b-x)), a =-1, b = 1 Chebyshev 2'nd kind
7 : p(x) = sqrt((x-a)/(b-x)), a = 0, b = 1
8 : p(x) = 1/sqrt(b-x), a = 0, b = 1
9 : p(x) = sqrt(b-x), a = 0, b = 1
trace : bool, optional
If non-zero a point plot of the integrand (default False).
gn : scalar integer
number of base points to start the integration with (default 2).
alpha, beta : real scalars, optional
Shape parameters of Laguerre or Jacobi weight function
(alpha,beta>-1) (default alpha=beta=0)
Returns
-------
val : ndarray
evaluated integral
err : ndarray
error estimate, absolute tolerance abs(int-intold)
Notes
-----
GAUSSQ numerically evaluate integral using a Gauss quadrature.
The Quadrature integrates a (2m-1)th order polynomial exactly and the
integral is of the form
b
Int (p(x)* Fun(x)) dx
a
GAUSSQ is vectorized to accept integration limits A, B and
coefficients P1,P2,...Pn, as matrices or scalars and the
result is the common size of A, B and P1,P2,...,Pn.
Examples
---------
integration of x**2 from 0 to 2 and from 1 to 4
>>> from scitools import numpyutils as npt
>>> A = [0, 1]; B = [2,4]
>>> fun = npt.wrap2callable('x**2')
>>> [val1,err1] = gaussq(fun,A,B)
>>> val1
array([ 2.6666667, 21. ])
>>> err1
array([ 1.7763568e-15, 1.0658141e-14])
Integration of x^2*exp(-x) from zero to infinity:
>>> fun2 = npt.wrap2callable('1')
>>> val2, err2 = gaussq(fun2, 0, npt.inf, wfun=3, alpha=2)
>>> val3, err3 = gaussq(lambda x: x**2,0, npt.inf, wfun=3, alpha=0)
>>> val2, err2
(array([ 2.]), array([ 6.6613381e-15]))
>>> val3, err3
(array([ 2.]), array([ 1.7763568e-15]))
Integrate humps from 0 to 2 and from 1 to 4
>>> val4, err4 = gaussq(humps,A,B)
See also
--------
qrule
gaussq2d
'''
def _get_dx(self, wfun, jacob, alpha, beta):
if wfun in [1, 2, 3, 7]:
dx = jacob
elif wfun == 4:
dx = jacob ** (alpha + beta + 1)
elif wfun == 5:
dx = ones((np.size(jacob), 1))
elif wfun == 6:
dx = jacob ** 2
elif wfun == 8:
dx = sqrt(jacob)
elif wfun == 9:
dx = sqrt(jacob) ** 3
11 years ago
else:
raise ValueError('unknown option')
return dx.ravel()
def _points_and_weights(self, gn, wfun, alpha, beta):
global _POINTS_AND_WEIGHTS
name = 'wfun%d_%d_%g_%g' % (wfun, gn, alpha, beta)
x_and_w = _POINTS_AND_WEIGHTS.setdefault(name, [])
if len(x_and_w) == 0:
x_and_w.extend(qrule(gn, wfun, alpha, beta))
xn, w = x_and_w
return xn, w
def _initialize_trace(self, max_iter):
if self.trace:
self.x_trace = [0] * max_iter
self.y_trace = [0] * max_iter
def _plot_trace(self, x, y):
if self.trace:
self.x_trace.append(x.ravel())
self.y_trace.append(y.ravel())
11 years ago
hfig = plt.plot(x, y, 'r.')
plt.setp(hfig, 'color', 'b')
def _plot_final_trace(self):
if self.trace > 0:
plt.clf()
plt.plot(np.hstack(self.x_trace), np.hstack(self.y_trace), '+')
def _get_jacob(self, wfun, A, B):
if wfun in [2, 3]:
nk = np.size(A)
jacob = ones((nk, 1))
11 years ago
else:
jacob = (B - A) * 0.5
if wfun in [7, 8, 9]:
jacob = jacob * 2
return jacob
11 years ago
def _warn(self, k, a_shape):
nk = len(k)
11 years ago
if nk > 1:
if (nk == np.prod(a_shape)):
tmptxt = 'All integrals did not converge'
else:
tmptxt = '%d integrals did not converge' % (nk, )
tmptxt = tmptxt + '--singularities likely!'
11 years ago
else:
tmptxt = 'Integral did not converge--singularity likely!'
warnings.warn(tmptxt)
def _initialize(self, wfun, a, b, args):
args = np.broadcast_arrays(*np.atleast_1d(a, b, *args))
a_shape = args[0].shape
args = [np.reshape(x, (-1, 1)) for x in args]
A, B = args[:2]
args = args[2:]
if wfun in [2, 3]:
A = zeros((A.size, 1))
return A, B, args, a_shape
def __call__(self, fun, a, b, releps=1e-3, abseps=1e-3, alpha=0, beta=0,
wfun=1, trace=False, args=(), max_iter=11):
self.trace = trace
gn = 2
A, B, args, a_shape = self._initialize(wfun, a, b, args)
jacob = self._get_jacob(wfun, A, B)
shift = int(wfun in [1, 4, 5, 6])
dx = self._get_dx(wfun, jacob, alpha, beta)
self._initialize_trace(max_iter)
# Break out of the iteration loop for three reasons:
# 1) the last update is very small (compared to int and to releps)
# 2) There are more than 11 iterations. This should NEVER happen.
dtype = np.result_type(fun((A+B)*0.5, *args))
nk = np.prod(a_shape) # # of integrals we have to compute
k = np.arange(nk)
opts = (nk, dtype)
val, val_old, abserr = zeros(*opts), ones(*opts), zeros(*opts)
for i in range(max_iter):
xn, w = self._points_and_weights(gn, wfun, alpha, beta)
x = (xn + shift) * jacob[k, :] + A[k, :]
pi = [xi[k, :] for xi in args]
y = fun(x, *pi)
self._plot_trace(x, y)
val[k] = np.sum(w * y, axis=1) * dx[k] # do the integration
if any(np.isnan(val)):
val[np.isnan(val)] = val_old[np.isnan(val)]
if 1 < i:
abserr[k] = abs(val_old[k] - val[k]) # absolute tolerance
k, = np.where(abserr > np.maximum(abs(releps * val), abseps))
nk = len(k) # of integrals we have to compute again
if nk == 0:
break
val_old[k] = val[k]
gn *= 2 # double the # of basepoints and weights
else:
self._warn(k, a_shape)
11 years ago
# make sure int is the same size as the integration limits
val.shape = a_shape
abserr.shape = a_shape
11 years ago
self._plot_final_trace()
return val, abserr
gaussq = _Gaussq()
11 years ago
def richardson(Q, k):
# license BSD
# Richardson extrapolation with parameter estimation
c = np.real((Q[k - 1] - Q[k - 2]) / (Q[k] - Q[k - 1])) - 1.
# The lower bound 0.07 admits the singularity x.^-0.9
11 years ago
c = max(c, 0.07)
R = Q[k] + (Q[k] - Q[k - 1]) / c
return R
def quadgr(fun, a, b, abseps=1e-5, max_iter=17):
'''
Gauss-Legendre quadrature with Richardson extrapolation.
[Q,ERR] = QUADGR(FUN,A,B,TOL) approximates the integral of a function
FUN from A to B with an absolute error tolerance TOL. FUN is a function
handle and must accept vector arguments. TOL is 1e-6 by default. Q is
the integral approximation and ERR is an estimate of the absolute error.
QUADGR uses a 12-point Gauss-Legendre quadrature. The error estimate is
based on successive interval bisection. Richardson extrapolation
accelerates the convergence for some integrals, especially integrals
with endpoint singularities.
Examples
--------
>>> import numpy as np
>>> Q, err = quadgr(np.log,0,1)
>>> quadgr(np.exp,0,9999*1j*np.pi)
(-2.0000000000122662, 2.1933237448479304e-09)
>>> quadgr(lambda x: np.sqrt(4-x**2),0,2,1e-12)
(3.1415926535897811, 1.5809575870662229e-13)
>>> quadgr(lambda x: x**-0.75,0,1)
(4.0000000000000266, 5.6843418860808015e-14)
>>> quadgr(lambda x: 1./np.sqrt(1-x**2),-1,1)
(3.141596056985029, 6.2146261559092864e-06)
>>> quadgr(lambda x: np.exp(-x**2),-np.inf,np.inf,1e-9) #% sqrt(pi)
(1.7724538509055152, 1.9722334876348668e-11)
>>> quadgr(lambda x: np.cos(x)*np.exp(-x),0,np.inf,1e-9)
(0.50000000000000044, 7.3296813063450372e-11)
See also
--------
QUAD,
QUADGK
'''
# Author: jonas.lundgren@saabgroup.com, 2009. license BSD
# Order limits (required if infinite limits)
9 years ago
a = np.asarray(a)
b = np.asarray(b)
11 years ago
if a == b:
Q = b - a
err = b - a
return Q, err
elif np.real(a) > np.real(b):
reverse = True
a, b = b, a
else:
reverse = False
# Infinite limits
11 years ago
if np.isinf(a) | np.isinf(b):
# Check real limits
if ~ np.isreal(a) | ~np.isreal(b) | np.isnan(a) | np.isnan(b):
raise ValueError('Infinite intervals must be real.')
# Change of variable
if np.isfinite(a) & np.isinf(b):
# a to inf
9 years ago
[Q, err] = quadgr(lambda t: fun(a + t / (1 - t)) / (1 - t) ** 2,
0, 1, abseps)
11 years ago
elif np.isinf(a) & np.isfinite(b):
# -inf to b
9 years ago
[Q, err] = quadgr(lambda t: fun(b + t / (1 + t)) / (1 + t) ** 2,
-1, 0, abseps)
11 years ago
else: # -inf to inf
9 years ago
[Q1, err1] = quadgr(lambda t: fun(t / (1 - t)) / (1 - t) ** 2,
0, 1, abseps / 2)
[Q2, err2] = quadgr(lambda t: fun(t / (1 + t)) / (1 + t) ** 2,
-1, 0, abseps / 2)
11 years ago
Q = Q1 + Q2
err = err1 + err2
# Reverse direction
if reverse:
Q = -Q
return Q, err
# Gauss-Legendre quadrature (12-point)
xq = np.asarray(
[0.12523340851146894, 0.36783149899818018, 0.58731795428661748,
0.76990267419430469, 0.9041172563704748, 0.98156063424671924])
wq = np.asarray(
[0.24914704581340288, 0.23349253653835478, 0.20316742672306584,
0.16007832854334636, 0.10693932599531818, 0.047175336386511842])
xq = np.hstack((xq, -xq))
wq = np.hstack((wq, wq))
nq = len(xq)
dtype = np.result_type(fun(a), fun(b))
11 years ago
# Initiate vectors
9 years ago
Q0 = zeros(max_iter, dtype=dtype) # Quadrature
Q1 = zeros(max_iter, dtype=dtype) # First Richardson extrapolation
Q2 = zeros(max_iter, dtype=dtype) # Second Richardson extrapolation
11 years ago
# One interval
hh = (b - a) / 2 # Half interval length
x = (a + b) / 2 + hh * xq # Nodes
# Quadrature
Q0[0] = hh * np.sum(wq * fun(x), axis=0)
# Successive bisection of intervals
for k in range(1, max_iter):
11 years ago
# Interval bisection
hh = hh / 2
x = np.hstack([x + a, x + b]) / 2
# Quadrature
9 years ago
Q0[k] = hh * np.sum(wq * np.sum(np.reshape(fun(x), (-1, nq)), axis=0),
axis=0)
11 years ago
# Richardson extrapolation
if k >= 5:
Q1[k] = richardson(Q0, k)
Q2[k] = richardson(Q1, k)
elif k >= 3:
Q1[k] = richardson(Q0, k)
# Estimate absolute error
11 years ago
if k >= 6:
Qv = np.hstack((Q0[k], Q1[k], Q2[k]))
Qw = np.hstack((Q0[k - 1], Q1[k - 1], Q2[k - 1]))
elif k >= 4:
Qv = np.hstack((Q0[k], Q1[k]))
Qw = np.hstack((Q0[k - 1], Q1[k - 1]))
else:
Qv = np.atleast_1d(Q0[k])
Qw = Q0[k - 1]
errors = np.atleast_1d(abs(Qv - Qw))
j = errors.argmin()
err = errors[j]
Q = Qv[j]
if k >= 2: # and not iscomplex:
_val, err1 = dea3(Q0[k - 2], Q0[k - 1], Q0[k])
# Convergence
if (err < abseps) | ~np.isfinite(Q):
break
else:
warnings.warn('Max number of iterations reached without convergence.')
if ~ np.isfinite(Q):
warnings.warn('Integral approximation is Infinite or NaN.')
# The error estimate should not be zero
err = err + 2 * np.finfo(Q).eps
# Reverse direction
if reverse:
Q = -Q
return Q, err
def boole(y, x):
a, b = x[0], x[-1]
n = len(x)
h = (b - a) / (n - 1)
return (2 * h / 45) * (7 * (y[0] + y[-1]) + 12 * np.sum(y[2:n - 1:4]) +
32 * np.sum(y[1:n - 1:2]) +
14 * np.sum(y[4:n - 3:4]))
def qdemo(f, a, b, kmax=9, plot_error=False):
11 years ago
'''
Compares different quadrature rules.
Parameters
----------
f : callable
function
a,b : scalars
lower and upper integration limits
Details
-------
qdemo(f,a,b) computes and compares various approximations to
the integral of f from a to b. Three approximations are used,
the composite trapezoid, Simpson's, and Boole's rules, all with
equal length subintervals.
In a case like qdemo(exp,0,3) one can see the expected
convergence rates for each of the three methods.
In a case like qdemo(sqrt,0,3), the convergence rate is limited
not by the method, but by the singularity of the integrand.
Example
-------
>>> import numpy as np
>>> qdemo(np.exp,0,3)
true value = 19.08553692
ftn, Boole, Chebychev
evals approx error approx error
3, 19.4008539142, 0.3153169910, 19.5061466023, 0.4206096791
5, 19.0910191534, 0.0054822302, 19.0910191534, 0.0054822302
9, 19.0856414320, 0.0001045088, 19.0855374134, 0.0000004902
17, 19.0855386464, 0.0000017232, 19.0855369232, 0.0000000000
33, 19.0855369505, 0.0000000273, 19.0855369232, 0.0000000000
65, 19.0855369236, 0.0000000004, 19.0855369232, 0.0000000000
129, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
257, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
513, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
ftn, Clenshaw-Curtis, Gauss-Legendre
evals approx error approx error
3, 19.5061466023, 0.4206096791, 19.0803304585, 0.0052064647
5, 19.0834145766, 0.0021223465, 19.0855365951, 0.0000003281
9, 19.0855369150, 0.0000000082, 19.0855369232, 0.0000000000
17, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
33, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
65, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
129, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
257, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
513, 19.0855369232, 0.0000000000, 19.0855369232, 0.0000000000
ftn, Simps, Trapz
evals approx error approx error
3, 19.5061466023, 0.4206096791, 22.5366862979, 3.4511493747
5, 19.1169646189, 0.0314276957, 19.9718950387, 0.8863581155
9, 19.0875991312, 0.0020622080, 19.3086731081, 0.2231361849
17, 19.0856674267, 0.0001305035, 19.1414188470, 0.0558819239
33, 19.0855451052, 0.0000081821, 19.0995135407, 0.0139766175
65, 19.0855374350, 0.0000005118, 19.0890314614, 0.0034945382
129, 19.0855369552, 0.0000000320, 19.0864105817, 0.0008736585
257, 19.0855369252, 0.0000000020, 19.0857553393, 0.0002184161
513, 19.0855369233, 0.0000000001, 19.0855915273, 0.0000546041
11 years ago
'''
true_val, _tol = intg.quad(f, a, b)
print('true value = %12.8f' % (true_val,))
neval = zeros(kmax, dtype=int)
vals_dic = {}
err_dic = {}
11 years ago
# try various approximations
methods = [trapz, simps, boole, ]
11 years ago
for k in range(kmax):
11 years ago
n = 2 ** (k + 1) + 1
neval[k] = n
x = np.linspace(a, b, n)
y = f(x)
for method in methods:
name = method.__name__.title()
q = method(y, x)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
name = 'Clenshaw-Curtis'
q, _ec3 = clencurt(f, a, b, (n - 1) / 2)
vals_dic.setdefault(name, []).append(q[0])
err_dic.setdefault(name, []).append(abs(q[0] - true_val))
name = 'Chebychev'
ck = np.polynomial.chebyshev.chebfit(x, y, deg=min(n-1, 36))
cki = np.polynomial.chebyshev.chebint(ck)
q = np.polynomial.chebyshev.chebval(x[-1], cki)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
# ck = chebfit(f,n,a,b)
# q = chebval(b,chebint(ck,a,b),a,b)
# qc2[k] = q; ec2[k] = abs(q - true)
name = 'Gauss-Legendre' # quadrature
11 years ago
q = intg.fixed_quad(f, a, b, n=n)[0]
# [x, w]=qrule(n,1)
11 years ago
# x = (b-a)/2*x + (a+b)/2 % Transform base points X.
# w = (b-a)/2*w % Adjust weigths.
# q = sum(feval(f,x)*w)
vals_dic.setdefault(name, []).append(q)
err_dic.setdefault(name, []).append(abs(q - true_val))
11 years ago
# display results
names = sorted(vals_dic.keys())
num_cols = 2
formats = ['%4.0f, ', ] + ['%10.10f, ', ] * num_cols * 2
formats[-1] = formats[-1].split(',')[0]
formats_h = ['%4s, ', ] + ['%20s, ', ] * num_cols
formats_h[-1] = formats_h[-1].split(',')[0]
headers = ['evals'] + ['%12s %12s' % ('approx', 'error')] * num_cols
while len(names) > 0:
print(''.join(fi % t for fi, t in zip(formats_h,
['ftn'] + names[:num_cols])))
print(' '.join(headers))
data = [neval]
for name in names[:num_cols]:
data.append(vals_dic[name])
data.append(err_dic[name])
data = np.vstack(tuple(data)).T
for k in range(kmax):
tmp = data[k].tolist()
print(''.join(fi % t for fi, t in zip(formats, tmp)))
if plot_error:
plt.figure(0)
for name in names[:num_cols]:
plt.loglog(neval, err_dic[name], label=name)
names = names[num_cols:]
if plot_error:
plt.xlabel('number of function evaluations')
plt.ylabel('error')
plt.legend()
plt.show('hold')
11 years ago
def main():
# val, err = clencurt(np.exp, 0, 2)
# valt = np.exp(2) - np.exp(0)
# [Q, err] = quadgr(lambda x: x ** 2, 1, 4, 1e-9)
# [Q, err] = quadgr(humps, 1, 4, 1e-9)
#
# [x, w] = h_roots(11, 'newton')
# sum(w)
# [x2, w2] = la_roots(11, 1, 't')
#
# from scitools import numpyutils as npu #@UnresolvedImport
# fun = npu.wrap2callable('x**2')
# p0 = fun(0)
# A = [0, 1, 1]; B = [2, 4, 3]
# area, err = gaussq(fun, A, B)
#
# fun = npu.wrap2callable('x**2')
# [val1, err1] = gaussq(fun, A, B)
#
#
# Integration of x^2*exp(-x) from zero to infinity:
# fun2 = npu.wrap2callable('1')
# [val2, err2] = gaussq(fun2, 0, np.inf, wfun=3, alpha=2)
# [val2, err2] = gaussq(lambda x: x ** 2, 0, np.inf, wfun=3, alpha=0)
#
# Integrate humps from 0 to 2 and from 1 to 4
# [val3, err3] = gaussq(humps, A, B)
#
# [x, w] = p_roots(11, 'newton', 1, 3)
# y = np.sum(x ** 2 * w)
11 years ago
x = np.linspace(0, np.pi / 2)
_q0 = np.trapz(humps(x), x)
[q, err] = romberg(humps, 0, np.pi / 2, 1e-4)
print(q, err)
11 years ago
def test_docstrings():
np.set_printoptions(precision=7)
import doctest
doctest.testmod()
11 years ago
if __name__ == '__main__':
test_docstrings()
# qdemo(np.exp, 0, 3, plot_error=True)
# plt.show('hold')
11 years ago
# main()