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325 lines
9.9 KiB
Python
325 lines
9.9 KiB
Python
8 years ago
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'''
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Created on 15. des. 2016
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@author: pab
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'''
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from __future__ import division
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from scipy import sparse
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import numpy as np
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from wafo.testing import test_docstrings
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from itertools import product
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__all__ = ['accum', 'gridcount']
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def bitget(int_type, offset):
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"""Returns the value of the bit at the offset position in int_type.
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Example
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-------
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>>> bitget(5, np.r_[0:4])
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array([1, 0, 1, 0])
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"""
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return np.bitwise_and(int_type, 1 << offset) >> offset
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def accumsum(accmap, a, shape, dtype=None):
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"""
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Example
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-------
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>>> from numpy import array
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>>> a = array([[1,2,3],[4,-1,6],[-1,8,9]])
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>>> a
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array([[ 1, 2, 3],
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[ 4, -1, 6],
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[-1, 8, 9]])
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>>> # Sum the diagonals.
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>>> accmap = array([[0,1,2],[2,0,1],[1,2,0]])
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>>> s = accumsum(accmap, a, (3,)
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>>> s
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array([ 9, 7, 15])
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"""
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if dtype is None:
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dtype = a.dtype
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shape = np.atleast_1d(shape)
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if len(shape) > 1:
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binx = accmap[:, 0]
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biny = accmap[:, 1]
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out = sparse.coo_matrix(
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(a.ravel(), (binx, biny)), shape=shape, dtype=dtype).tocsr()
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else:
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binx = accmap.ravel()
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zero = np.zeros(len(binx))
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out = sparse.coo_matrix(
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(a.ravel(), (binx, zero)), shape=(shape, 1), dtype=dtype).tocsr()
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return out
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def accumsum2(accmap, a, shape):
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"""
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Example
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-------
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>>> from numpy import array
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>>> a = array([[1,2,3],[4,-1,6],[-1,8,9]])
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>>> a
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array([[ 1, 2, 3],
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[ 4, -1, 6],
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[-1, 8, 9]])
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>>> # Sum the diagonals.
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>>> accmap = array([[0,1,2],[2,0,1],[1,2,0]])
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>>> s = accumsum2(accmap, a, (3,)
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>>> s
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array([ 9, 7, 15])
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"""
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return np.bincount(accmap.ravel(), a.ravel(), np.array(shape).max())
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def accum(accmap, a, func=None, size=None, fill_value=0, dtype=None):
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"""An accumulation function similar to Matlab's `accumarray` function.
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Parameters
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----------
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accmap : ndarray
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This is the "accumulation map". It maps input (i.e. indices into
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`a`) to their destination in the output array. The first `a.ndim`
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dimensions of `accmap` must be the same as `a.shape`. That is,
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`accmap.shape[:a.ndim]` must equal `a.shape`. For example, if `a`
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has shape (15,4), then `accmap.shape[:2]` must equal (15,4). In this
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case `accmap[i,j]` gives the index into the output array where
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element (i,j) of `a` is to be accumulated. If the output is, say,
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a 2D, then `accmap` must have shape (15,4,2). The value in the
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last dimension give indices into the output array. If the output is
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1D, then the shape of `accmap` can be either (15,4) or (15,4,1)
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a : ndarray
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The input data to be accumulated.
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func : callable or None
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The accumulation function. The function will be passed a list
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of values from `a` to be accumulated.
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If None, numpy.sum is assumed.
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size : ndarray or None
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The size of the output array. If None, the size will be determined
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from `accmap`.
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fill_value : scalar
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The default value for elements of the output array.
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dtype : numpy data type, or None
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The data type of the output array. If None, the data type of
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`a` is used.
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Returns
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-------
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out : ndarray
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The accumulated results.
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The shape of `out` is `size` if `size` is given. Otherwise the
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shape is determined by the (lexicographically) largest indices of
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the output found in `accmap`.
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Examples
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--------
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>>> from numpy import array, prod
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>>> a = array([[1,2,3],[4,-1,6],[-1,8,9]])
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>>> a
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array([[ 1, 2, 3],
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[ 4, -1, 6],
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[-1, 8, 9]])
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>>> # Sum the diagonals.
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>>> accmap = array([[0,1,2],[2,0,1],[1,2,0]])
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>>> s = accum(accmap, a)
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>>> s
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array([ 9, 7, 15])
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>>> # A 2D output, from sub-arrays with shapes and positions like this:
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>>> # [ (2,2) (2,1)]
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>>> # [ (1,2) (1,1)]
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>>> accmap = array([
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... [[0,0],[0,0],[0,1]],
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... [[0,0],[0,0],[0,1]],
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... [[1,0],[1,0],[1,1]]])
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>>> # Accumulate using a product.
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>>> accum(accmap, a, func=prod, dtype=float)
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array([[ -8., 18.],
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[ -8., 9.]])
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>>> # Same accmap, but create an array of lists of values.
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>>> accum(accmap, a, func=lambda x: x, dtype='O')
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array([[[1, 2, 4, -1], [3, 6]],
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[[-1, 8], [9]]], dtype=object)
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"""
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def create_array_of_python_lists(accmap, a, size):
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vals = np.empty(size, dtype='O')
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for s in product(*[range(k) for k in size]):
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vals[s] = []
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for s in product(*[range(k) for k in a.shape]):
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indx = tuple(accmap[s])
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val = a[s]
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vals[indx].append(val)
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return vals
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# Check for bad arguments and handle the defaults.
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if accmap.shape[:a.ndim] != a.shape:
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raise ValueError(
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"The initial dimensions of accmap must be the same as a.shape")
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if func is None:
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func = np.sum
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if dtype is None:
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dtype = a.dtype
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if accmap.shape == a.shape:
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accmap = np.expand_dims(accmap, -1)
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adims = tuple(range(a.ndim))
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if size is None:
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size = 1 + np.squeeze(np.apply_over_axes(np.max, accmap, axes=adims))
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size = np.atleast_1d(size)
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# Create an array of python lists of values.
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vals = create_array_of_python_lists(accmap, a, size)
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# Create the output array.
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out = np.empty(size, dtype=dtype)
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for s in np.product(*[range(k) for k in size]):
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if vals[s] == []:
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out[s] = fill_value
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else:
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out[s] = func(vals[s])
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return out
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def gridcount(data, X, y=1):
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'''
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Returns D-dimensional histogram using linear binning.
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Parameters
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----------
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data = column vectors with D-dimensional data, shape D x Nd
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X = row vectors defining discretization, shape D x N
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Must include the range of the data.
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Returns
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-------
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c = gridcount, shape N x N x ... x N
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GRIDCOUNT obtains the grid counts using linear binning.
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There are 2 strategies: simple- or linear- binning.
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Suppose that an observation occurs at x and that the nearest point
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below and above is y and z, respectively. Then simple binning strategy
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assigns a unit weight to either y or z, whichever is closer. Linear
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binning, on the other hand, assigns the grid point at y with the weight
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of (z-x)/(z-y) and the gridpoint at z a weight of (y-x)/(z-y).
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In terms of approximation error of using gridcounts as pdf-estimate,
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linear binning is significantly more accurate than simple binning.
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NOTE: The interval [min(X);max(X)] must include the range of the data.
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The order of C is permuted in the same order as
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meshgrid for D==2 or D==3.
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Example
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-------
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>>> import numpy as np
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>>> import wafo.kdetools as wk
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>>> import pylab as plb
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>>> N = 20
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>>> data = np.random.rayleigh(1,N)
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>>> data = np.array(
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... [ 1.07855907, 1.51199717, 1.54382893, 1.54774808, 1.51913566,
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... 1.11386486, 1.49146216, 1.51127214, 2.61287913, 0.94793051,
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... 2.08532731, 1.35510641, 0.56759888, 1.55766981, 0.77883602,
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... 0.9135759 , 0.81177855, 1.02111483, 1.76334202, 0.07571454])
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>>> x = np.linspace(0,max(data)+1,50)
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>>> dx = x[1]-x[0]
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>>> c = wk.gridcount(data, x)
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>>> np.allclose(c[:5], [ 0., 0.9731147, 0.0268853, 0., 0.])
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True
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>>> pdf = c/dx/N
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>>> np.allclose(np.trapz(pdf, x), 1)
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True
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h = plb.plot(x,c,'.') # 1D histogram
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h1 = plb.plot(x, pdf) # 1D probability density plot
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See also
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--------
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bincount, accum, kdebin
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Reference
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----------
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Wand,M.P. and Jones, M.C. (1995)
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'Kernel smoothing'
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Chapman and Hall, pp 182-192
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'''
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dat = np.atleast_2d(data)
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x = np.atleast_2d(X)
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y = np.atleast_1d(y).ravel()
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d = dat.shape[0]
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d1, inc = x.shape
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if d != d1:
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raise ValueError('Dimension 0 of data and X do not match.')
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dx = np.diff(x[:, :2], axis=1)
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xlo = x[:, 0]
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xup = x[:, -1]
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datlo = dat.min(axis=1)
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datup = dat.max(axis=1)
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if ((datlo < xlo) | (xup < datup)).any():
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raise ValueError('X does not include whole range of the data!')
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csiz = np.repeat(inc, d)
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use_sparse = False
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if use_sparse:
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acfun = accumsum # faster than accum
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else:
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acfun = accumsum2 # accum
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binx = np.asarray(np.floor((dat - xlo[:, np.newaxis]) / dx), dtype=int)
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w = dx.prod()
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if d == 1:
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x.shape = (-1,)
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c = np.asarray((acfun(binx, (x[binx + 1] - dat) * y, shape=(inc, )) +
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acfun(binx + 1, (dat - x[binx]) * y, shape=(inc, ))) /
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w).ravel()
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else: # d>2
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Nc = csiz.prod()
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c = np.zeros((Nc,))
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fact2 = np.asarray(np.reshape(inc * np.arange(d), (d, -1)), dtype=int)
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fact1 = np.asarray(
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np.reshape(csiz.cumprod() / inc, (d, -1)), dtype=int)
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# fact1 = fact1(ones(n,1),:);
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bt0 = [0, 0]
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X1 = X.ravel()
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for ir in range(2 ** (d - 1)):
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bt0[0] = np.reshape(bitget(ir, np.arange(d)), (d, -1))
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bt0[1] = 1 - bt0[0]
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for ix in range(2):
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one = np.mod(ix, 2)
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two = np.mod(ix + 1, 2)
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# Convert to linear index
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# linear index to c
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b1 = np.sum((binx + bt0[one]) * fact1, axis=0)
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bt2 = bt0[two] + fact2
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b2 = binx + bt2 # linear index to X
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c += acfun(b1, np.abs(np.prod(X1[b2] - dat, axis=0)) * y,
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shape=(Nc,))
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c = np.reshape(c / w, csiz, order='F')
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T = [i for i in range(d)]
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T[1], T[0] = T[0], T[1]
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# make sure c is stored in the same way as meshgrid
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c = c.transpose(*T)
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return c
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if __name__ == '__main__':
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test_docstrings(__file__)
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